The ribbon required to be combined is 48 inches but he had only 36 inches. so, he does not have enough ribbons.
Given that,
Troy is making a flag-shaped like a square.
Each side measure 12 inches.
He wants to add a ribbon along the edges. He has 36 inches of ribbon.
We have to determine,
Does he have enoughribbon?
According to the question,
A square has 4 sides, and all sides have the same length.
If one side measures 12 inches, then the total length of all sides is,
= 4 × 12 inches = 48 inches
All edges combined are a total of 48 inches.
He only has 36 inches of ribbon, so he does not have enough ribbon.
Hence, The ribbon required to be combined is 48 inches but he had only 36 inches. so, he does not have enough ribbons.
To know more about Square click the link given below.
Answer:
The first mechanic $90/hour and the second charged $70/hour
Step-by-step explanation:
Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:
5x+10y = 1150
We also know that together they charged 160/per hour. An equation to express this would be:
x+y = 160
Now we can solve the second equation for x or the first mechanics rate.
x+y = 160
x = 160 - y
Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.
5x+10y=1150 plug in x =160-y
5(160-y)+10y=1150 Distribute
800 -5y+10y = 1150 Combine like terms
800 +5y = 1150 Subtract 800 from both sides
5y = 350 divide by 5
y = 70
So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.
x = 160-y
x = 160-70
x = 90
So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.
The rate per hour for the first mechanic is $105 and for the second mechanic is $85.
This problem is a case of simultaneous equations where we need to determine the rates at which the two mechanics charge. Let's denote the hourly rates of the first and second mechanics as x and y respectively. From the question, we know:
1. x + y = $190 (The sum of the two rates was $190 per hour)
2. 10x + 5y = $1475 (The first mechanic worked for 10 hours and the second mechanic worked for 5 hours, and together they charged a total of $1475)
To solve these equations, you can start by multiplying the first equation by 5 to match the second equation:
5x + 5y = $950
Now, subtract this from the second equation:
10x - 5x = $1475 - $950
5x = $525
Therefore, x ($/hour by the first mechanic) = $525 / 5 = $105
You can now substitute x = $105 into the first equation to get:
$105 + y = $190
Therefore, y ($/hour by the second mechanic) = $190 - $105 = $85
#SPJ2
Answer:
Step-by-step explanation:
Surface area is 2(πr²) + 2πrh. The first includes the top and bottom; the second is the area of lateral sides of the cylinder (radius r and height h).
The volume of this cylinder is V = πr²h.
Answer:
2 pi r square + pi dh
Step-by-step explanation:
2 pi r square + pi dh
Answer:
The diameter= 28in
Step-by-step explanation: