Let x be the rate of speed of slower cyclist
and x+10 = rate of speed of faster cyclist
Distance = Speed * Time
5x + 5(x+10) = 200
5x + 5x + 50 = 200
10x = 200-50
10x = 150
x = 15
Rate of speed of slower cyclist: 15 mph
Rate of speed of faster cyclist = 15+10 => 25 mph
In this problem, the speed of the faster cyclist is 25 mi/h and the speed of the slower cyclist is 15 mi/h. We determine this by setting up and solving an algebraic equation considering the total distance and time they traveled.
This problem is a typical example of relativerate and distance problems in algebra. First, define the speed of the faster cyclist as x m/h. Then, the speed of the slower cyclist is x-10 m/h. They travel towards each other, so their rates add up. That's why the equation becomes x+(x-10) = 200/5. We get this equation because the total distance they traveled is 200 miles (meeting in the middle), and they traveled for 5 hours.
Solving the equation x+(x-10) = 40 gives 2x-10 = 40, then 2x = 50, and finally x = 25. So, the faster cyclist is moving at 25 mi/h, and the slower cyclist is moving at 15 mi/h (25-10).
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Answer:
The answer is explained below.
Step-by-step explanation:
In this case, all of the offspring are black. For this to happen, the following conditions must occur:
The B must be the dominant gene. Besides that, it is necessary to point out that both parents are black, which directly impacts the offspring, making them the same color.
STEPS:
First distribute the 5 through the parentheses to get 5q + 135. So the problem now reads 5q + 135 - (-30) = 95.
Now, minus a negative can be changed to plus a positive so - (-30) can be changed to +30 so our equation now reads 5q + 135 + 30 = 95.
Before adding or subtracting anything from both sides of the equation, make sure you simplify the left side as much as possible. Notice that we can add 135 and 30 to get 165 so the left side simplifies to 5q + 165 = 95.
Now we can simply subtract 165 from both sides of the equation to get 5q = -70.
Now simply divide both sides of the equation by 5 to get q = -14.
(b) 449.02 ft² (d) 530.66 ft²
please help!!!!!
ANSWER:
STEP:
Add 8 and 5. You cannot add a number t a variable. So leave 4x+13 as the way it is.