mosquitoes get their food by sucking other animals blood, sometimes giving it disease. what type of symbiosis is this.

Answer:

0.172 mol·L⁻¹

Step-by-step explanation:

1. Write the chemical equation for the reaction.

HBr + LiOH ⟶ LiBr + H₂O

===============

2. Calculate the moles of LiOH

c = n/V         Multiply each side by V

n = Vc

V = 0.0375 L

c = 0.215 mol·L⁻¹

Moles of LiOH = 0.0375× 0.215

Moles of LiOH = 8.062 × 10⁻³ mol LiOH

===============

3. Calculate the moles of HBr

1 mol HBr ≡ 1 mol LiOH

Moles of HBr = 8.062 × 10⁻³× 1/1

Moles of HBr = 8.062 × 10⁻³ mol HBr

===============

4. Calculate the molar concentration of the HBr

V = 47.0 mL = 0.0470 L

c = 8.062 × 10⁻³/0.0470

c = 0.172 mol·L⁻¹

The molarity of the HBr solution is 0,172 M.

The neutralization reaction between LiOH and HBr is the following:

HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)

The gravitational potential energy not only depends on the mass of the substance but also on the height it positioned. Hence, two objects with same mass does not have same potential energy if they are not in same height.

What is gravitational potential energy?

Gravitational potential energy of an object is the energy generated by virtue of  its position in gravitational field.  Gravitational force is exerted by one object by which it attracts other objects into its centre of mass.

The gravitational force is dependant upon the mass of the object as well to the distance between the objects. Similarly the potential energy p is proportional to the mass m, gravity g and the height from the surface h.

Hence p = mgh.

As per this relation potential energy is not only affected by the mass but also the height at which the objects are located.

If an object is placed at a height higher than other object having same mass then it stores greater potential energy. Hence, we can't agree with the statement .

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Answer:

the above screenshot has the answers

A particle diagram showing the composition of air would represent various gases like nitrogen, oxygen, water vapor, and carbon dioxide as spheres of different colors. The proportions between these gases would be shown by having a majority of nitrogen and oxygen spheres as they make up most of our atmosphere. The diagram may also include symbols for dust particles and particulate matter.

A particle diagram to illustrate the composition of air would visually represent the mixture of gases that comprise our atmosphere. Primarily, the atmospheric mix includes nitrogen (N₂; 78.6 percent), oxygen (O₂; 20.9 percent), water vapor (H₂O; 0.5 percent), and carbon dioxide (CO₂; 0.04 percent).

Each of these gases exist as molecules, with nitrogen and oxygen being diatomic. In other words, their molecules consist of two atoms.

In such a diagram, each type of atom would be represented as a sphere of a different color, for instance, nitrogen atoms might be blue, oxygen red, hydrogen white, and carbon grey.

The proportions would be represented by having a larger number of nitrogen and oxygen spheres compared to water vapor and carbon dioxide.

Furthermore, there might be additional entities in the diagram to represent dust particles or other environmental particulate matter suspended in the air. This allows us to get a qualitative understanding of the composition of Earth's atmosphere and mechanisms that drive gas exchange.

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Answer:

848.1 g/mol

Explanation:

Data given:

Standard of atomic mass of Ca = 50 amu

molar mass of Aluminium Acetate = ?

Solution:

Relative atomic mass represented by Ar. It is ratio of actual mass with respect to the 1/12th mass of C-12 but here Ca-50 is standard.

Formula of  Aluminium Acetate = Al(CH₃COO)₃

In order to calculate Ar

first we will calculate 1/50 of Ca

As we know

         mass of 1/12 of C-12 = 1.993 x 10⁻²⁶/12 = 1.661 x 10⁻²⁷ Kg

So, for Ca-50

        mass of 1/50 of Ca-50 = 1.993 x 10⁻²⁶/50 = 3.986 x 10⁻²⁸ Kg

Now

 Relative Atomic mass for element X = rest mass of "X"/ 3.986 x 10⁻²⁸ Kg . . . . . . (1)

First we have to know the relative atomic masses of Aluminium, carbon, hydrogen, oxygen atoms involve in Aluminium Acetate formula with respect to new standard Ca-50

By using equation-1 we can calculate Ar for which we have reported rest masses of atoms as below

Rest mass of Aluminium = 4.48 x 10⁻²⁶ Kg

Rest mass of carbon = 1.993 x 10⁻²⁶ Kg

Rest mass of hydrogen = 1.608 x 10⁻²⁷ Kg

Rest mass of oxygen = 2.657x10⁻²⁶ Kg

Now put values in equation 1 for each atom

• Ar for Aluminium= 4.48 x 10⁻²⁶Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for Aluminium = 112.5  amu

• Ar for Carbon= 1.993 x 10⁻²⁶ Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for Carbon= 50 amu

• Ar for Hydrogen = 1.608 x 10⁻²⁷ Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for hydrogen = 4  amu

• Ar for Oxygen = 2.657x10⁻²⁶ Kg / 3.986 x 10⁻²⁸ Kg

                     Ar for Oxygen = 66.6  amu

Now find the molar mass ofAl(CH₃COO)₃

molar mass of Aluminium Acetate = Al(CH₃COO)₃

Al(CH₃COO)₃ = 112.5 + 3 (50 + 3(4) + 50 + 66.6 +66.6)

Al(CH₃COO)₃ = 112.5 + 3 (50 + 12 + 50 + 66.6 +66.6)

Al(CH₃COO)₃ = 112.5 + 3 (245.2)

Al(CH₃COO)₃ = 112.5 + 735.6

Al(CH₃COO)₃ = 848.1 g/mol

molar mass of Aluminium Acetate = 848.1 g/mol