A leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. At that rate how many gallons of water will the faucet leak in 48 hours.
Answers
To solve this problem, let's set up a proportion, letting x represent the unknown number of gallons the faucet loses in 48 hours.
5 gallons / 20 hours = x gallons / 48 hours
To solve this proportion, we are going to use cross-products. This is the products of numerator of one fraction and the denominator of the other fraction set equal to one another. It results in the equation:
5 * 48 = 20 * x
Next we simplify by performing the operations.
240 = 20x
Finally, we divide both sides by 20 to get x alone on the right side of the equation.
12=x
Therefore, 12 gallons of water will be lost in 48 hours.
5gallons leakout every 20 hours 5g:20h fractionify 5g/20h=g/4h g:4h
how many gallons in 48 hours xgallons:48 assume constant rate of flow so g:4h=x:48 fractionfy g/4h=x/48h multiply both sides by 48h 12g=x answer is 12 gallons
What's is 7x90 it not hard it's not easy it medium
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90 × 7 = 630 , it's not hard, it's easy
Answer:
630
Step-by-step explanation:
Thanks For helping me answer my question
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Answer:
your welcome
Step-by-step explanation:
have a good day
Y=3x-4 is the line linear
Answers
Yes, the line is linear
Slope passing through the points of (3,-3) and (2,-5)