A cone is placed inside a cylinder as shown. The radius of the cone is half the radius of the cylinder. The height of the cone is equal to the radius of the cylinder. What is the volume of the cone in terms of the radius, r?

Answers

Answer 1

Answer: Given:
Let us assume the radius of the cylinder is x.
radius of the cone is half the radius of the cylinder: x/2
height of the cone is equal to the radius of the cylinder: x

radius of cone: x/2 ; height of the cone: x

volume of the the cone = π r² h/3
V = 3.14 * (x/2)² * x/3
V = 3.14 * x²/4 * x/3
V = (3.14 * x² * x)/4*3
V = 3.14 x³ / 12

Answer 2

Answer:

Answer:

(1/12) Pi r^3 option C on plato

Step-by-step explanation:

r = radius of the cylinder

V = (1/3)Pi c^2 h for a cone.

and c = r/2 and h = u

so Volume of the cone is (1/12) Pi r^3

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What's the answer for 4820 divided 241

Answers

Answer:

Step-by-step explanation:

241×2=482

so; 241×20=4820

At a local bodega, the cost of a bottle of juice at the corner store is$1.05, and the cost of a bag of chips is $1.10. What would it cost to get
8 bottles of juice and 4 bags of chips? What would it cost to get a
bottles of juice and y bags of chips?
Total cost, 8 bottles of juice and 4 bags of chips:
Total cost, x bottles of juice and y bags of chips:
y

Answers

Answer:

$12.80

Step-by-step explanation:

The cost to get 8 bottles of juice and 4 bags of chips will be:

= 8($.105) + 4($1.10)

= $8.40 + $4.40

= $12.80

The cost for x bottles of juice and y bags of chips will be:

= (1.05 × x) + (1.10 × y)

= 1.05x + 1.10y

Doug bought a new car for $25,000. He estimates his car will depreciate, or lose value, at a rate of 20% per year. The value of his car is modeled by the equation V = P(1 – r)t, where V is the value of the car, P is the price he paid, r is the annual rate of depreciation, and t is the number of years he has owned the car. According to the model, what will be the approximate value of his car after mc013-1.jpg years?$2,500
$9,159
$22,827
$23,802