MATHEMATICS HIGH SCHOOL

Please help asap 29 pts

Answers

Answer 1

Answer:

-|6-18|

-|-12|

-12

Answer -12

ChoiceD

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How will adding the value 1000 affect the mean and median of the data set 5, 10, 17, 19, 20? A.
The median increases and the mean stays the same.

B.
The mean and the median increase by the same amount.

C.
The mean increases more than the median increases.

D.
The mean increases and the median stays the same.

Answers

The answer should be C

How many positive integers less than 1,000 do not have 7 as any digit?

Answers

Calculate the numbers that do have 7 in it.
1 to 10 :1
70 to 79:10
1 to 100:1×9+10=19
700 to 799:100
1 to 999:8×19+100=252

intergers with no 7=999-252=747

Use the Quadratic Formula to solve

x²-13x+42=0

Answers

Answer:

x1=7,

x2=6

Step-by-step explanation:

x²-13x+42=0

a=1, b=-13, c=42

x1,2=(-b+-sqrt(b^2-4ac)) /2a

x1,2=(-(-13)+-sqrt((-13)^2-4*1*42))/2*1

x1,2=(13+-sqrt (169-168))/2

x1,2=(13+-sqrt(1))/2

x1,2=(13+-1)/2

x1=(13+1)/2, x2=(13-1)/2

x1=14/2, x2=12/2

x1=7, x2 =6

A bag contains 6 red jelly beans, 4 green jelly beans, and 4blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?

Answers

The probability of picking a green jelly bean with the first pick is 4/14 = 2/7, because there are 14 jelly bean in total (6 red + 4 green + 4 blue) and 4 of them are green.

If you pick a green jelly bean at the beginning, you have 13 jelly beans remaining, of which 6 are red. So, the probability of picking a red jelly bean is now 6/13.

You want these two events to happen one after the other, to be more precise you want to pick a green jelly bean with the first pick AND a red jelly bean with the second pick. We know the probabilities of the two events, so we have to multiply them to get the probability of them happening both:

$(2)/(7)\cdot(6)/(13)=(12)/(91)$

{–½, 2}{–½, –2}
{½, 2}
{½, –2} Use the quadratic formula to solve 2y2 – 5y = –2.

Answers

$2y^2 - 5y =-2\n \n2y^2 - 5y +2=0\n \n a=2 , \ b=-5, \ c=2 \n \n\Delta =b^2-4ac = (-5)^2 -4\cdot2\cdot 2 = 25-16=9 \n \ny_(1)=(-b-√(\Delta) )/(2a)=(5-√(9))/(2\cdot 2 )=(5-3)/(4)=(2)/(4)= (1)/(2)$

$y_(2)=(-b+√(\Delta) )/(2a)=(5+√(9))/(2\cdot 2 )=(5+3)/(4)=(8)/(4)= 2\n \nAnswer : \ \left \{ (1)/(2),2 \right \}$

Answer:

1/2, 2

Step-by-step explanation:

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