Which type of tape is used to round sharp edges on splices using larger conductors?a. Friction tape
b. Rubber tape
c. Cotton tape
d. Plastic tape

Answers

Answer 1
Answer: Rubber tape is used to round sharp edges
Answer 2
Answer:

Answer:

Explanation:

the answer is rubber tape not friction tape


Related Questions

Gravity causes___ objects to accelerate
Which type of waves from the electromagnetic spectrum are used in heat lamps and heat sensing devices? visible light ultraviolet rays radio waves infrared waves
What Is Solar Radiation?
Matter behaving like a wave rather than like a particle is best illustrated by which phenomenon?
CondensationRadiationConvectionConduction transfers heat within the atmosphere and ocean.

The density of mercury is 13.6 g/mL. What is the volume of a 155-gram sample of mercury?

Answers

The volume of a 155-gram sample of mercury is 11.397 mL if the density of mercury is 13.6 g/mL.

What is density?

It is defined as the mass-to-volume ratio. The density indicates the object's density and is represented by the symbol. The density is measured in kilograms per cubic meter.

It is given that:

The density of mercury is 13.6 g/mL.

The mass of the mercury is 155 grams.

As we know,

Volume can be defined as a three-dimensional space enclosed by an object or thing.

The density = mass/volume

13.6 = 155/volume

volume = 155/13.6

volume = 11.397 mL

Thus, the volume of a 155-gram sample of mercury is 11.397 mL if the density of mercury is 13.6 g/mL.

Learn more about the density here:

brainly.com/question/952755

#SPJ2

You need to use the density formula.

D = (m)/(V) 

DV = m

V = (m)/(D)

V = (155gHg)/(13.6(g)/(mL)Hg)

V = 11.397mL 

Which countries did President G.W. Bush include in his “axis of evil”?a. North Korea and Iran
b. Cuba and Venezuela
c. Russia and China
d. Egypt and Afghanistan

Answers


The answer is A. North Korea and Iran.
That is correct the answer is (A)North Korea and Iran. 

How is the resistor of a 40v lamp higher then the resistor of a 60v lamp?

Answers

Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
quantity of power dissipated, you can see that when the supply voltage is constant,
the smaller resistance dissipates more power.

So the 40w lamp has higher resistance than the 60w bulb.

A dock worker loading crates on a ship finds that a 24 kg crate, initially at rest on a horizontal surface, requires a 65 N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 50 N is required to keep it moving with a constant speed. The acceleration of gravity is 9.8 m/s 2 . Find the coefficient of static friction between crate and floor.

Answers

Answer:

0.276

Explanation: Here we have to consider the kinetic friction force acting on the body. If it is going at a constant speed according to newton's 1 st law. There was'not net force induced at the system. There for kinetic friction foce must be equal to the 50N .

But here we have been asked to get cofficient of static friction . There for you have to get static friction force. It should be 65N.

Mass of the object is 24. Then the reaction between surface and the object would be 24*9.8 = 235.2 N

There for using this,

Static friction force = Cofficient of static friction * Reaction

Cofficient of static friction = 65/235.2

= 0.276

Answer:

\mu_s=0.276

\mu_k=0.213

Explanation:

It is given that,

Mass of the crate, m = 24 kg

Force acting on the crate when it is at rest, F_r=65\ N

When the crate is in motion, force acting on the crate, F_m=55\ N

To find,

The coefficient of static friction between crate and floor

Solution,

When the crate is at rest, the force acting on the crate is given by :

F_r=\mu_sN

65=\mu_s* 24* 9.8

\mu_s=0.276

When the crate is in motion, the force acting on the crate is given by :

F_s=\mu_kN

50=\mu_k* 24* 9.8

\mu_k=0.213

Hence, this is the required solution.

A baseball player runs 27.4 meters from thebatter’s box to first base, overruns first base by
3.0 meters, and then returns to first base.
Compared to the total distance traveled by the
player, the magnitude of the player’s total
displacement from the batter’s box is
(1) 3.0 m shorter (3) 3.0 m longer
(2) 6.0 m shorter (4) 6.0 m longer

Answers

Distance is a measure of the length of space covered over a certain period of time. While displacement is the change in position of an object from its starting point. Displacement is 6.0 meters shorterthan distance.

  • Starting position = batter'box

  • Batter's box to first base = 27.4 meters

  • Distance beyond first base = 3 metres

  • Final position = first base

Total distance covered :

(Batter's box - > first base) + (beyond first base) + (return to first base)

  • (27.4 + 3 + 3) = 33.4 meters

Total Displacement :

(Batter's box - > first base) + (beyond first base) - (return to first base)

  • (27.4 + 3 - 3) = 27.4 meters

Difference in magnitude of Distance and Displacement :

  • 33.4 - 27.4 = 6.0 meters

Therefore, displacement is 6m shorter

Learn more :brainly.com/question/8283882

Answer:

(2) 6.0 m shorte.

Explanation:

Total distance = Distance from batter’s base to first base + Distance covered in overrunning + Distance covered in returning to first base  

Total Distance = 27.4 + 3 + 3 = 33.4 m

Total displacement = Displacement from batter’s base to first base + Displacement covered in overrunning + Displacement covered in to returning first base  

The 2nd and 3rd term will have same magnitude but opposite direction so, they will cancel out each other. Hence,  

Total Displacement = 27.4 m  

Hence, displacement will be 6.0 m shorter than distance.

A diver who weighs 500 N steps off a diving board that is 10 m above the water. The diver hits the water with kinetic energy of 8) _______ A) 10 J. B) 500 J. C) 5000 J. D) more than 5000 J. E) 510 J.

Answers

Answer:

C) 5000 J

Explanation:

when diver is at some height , he is having some energy in the form of potential energy. when he dives, his potential energy is converted into kinetic energy . so kinetic energy and potential energy are equal.

Kinetic energy of diver = potential energy of diver

= mgh

= 500 x 10

= 5000 J .