Let's solve this by using the quadratic formula:
Note that we only use the coefficients so a=12, b=-14, and c=-6.
Plug values in the quadratic equation:
And so by evaluating those values we obtain:
Now we have two answers which are our factors one where we add another where we subtract and so:
First factor:
Second Factor:
And so your factors are
meaning that those are your roots/x-intercepts.
what is: x + 3 - 2x -1 = 4 5 3
Answer:
X= -46/7
Step-by-step explanation:
step1: left part times 15 is 3(X+3)-5(2X-1)
step2: right part times 15 is 60
step3: 3(X+3)-5(2X-1)=60
step4: 3X+9-10X+5=60
step5: -7X+14=60
step6: -7X=46
step7: X= -46/7
Answer:
A = 90.25 pi in^2
Step-by-step explanation:
The circumference is given by
C = 2*pi*r
19pi = 2*pi*r
Divide each side by 2 pi
19pi / 2 pi = 2*pi*r/ 2pi
9.5 = r
The area is given by
A = pi r^2
A = pi ( 9.5)^2
A = 90.25 pi in^2
Answer:
The area of circle is 90.25 π inches².
Step-by-step explanation:
Given:-
Circumference of circle is 19 π in.
To Find :-
Area of circle
Solution :-
Firstly, we need to find radius of circle
Using formula
Circumference of circle = 2 π r
substitute the value
19 π inches = 2 π r
Divide each side by 2 π
19 π inches / 2 π = 2 π r / 2 π
9.5 inches = r
Now, Finding the area of circle
Using formula
Area of circle = π × r²
Where,
Substitute the values
Area of circle = π × ( 9.5 inches)²
Evaluate the exponent
Area of circle = π × 90.25 inches ²
multiply ,we get
Area of circle = 90.25 inches²
Hence, the area of circle is 90.25 π inches².
6x + 3y =
A: –12
B: –4
C: 0
D: 4
E: 12
For this case we have the following system of equations:
Rewriting equation 1 we have:
Therefore, the equivalent system is:
The system will have no solution, if we write equation 2 as a linear combination of equation 1.
Therefore, since both lines have the same slope, they are parallel.
Parallel lines do not intersect when they have different cut points.
Therefore, there is no solution for:
-12, -4, 0, 4
The system has inifinites solutions for:
12
This is because the lines intersect at all points in the domain.
Answer:
The values, when placed in the box, would result in a system of equations with no solution are:
A: -12
B: -4
C: 0
D: 4
Answer:
Thus, option (a), (b) , (c) , (d) are correct.
The system will have no solution for all values except 12.
Step-by-step explanation:
Given a system of equation y = –2x + 4 and 6x + 3y = ?
We have to check for which value the '?' would result in a system of equations with no solution.
Consider a system of equation
For the system to have no solution the condition is,
For the given system of equation ,
Let unknown quantity be v.
y = –2x + 4 ⇒ 2x +y - 4 = 0
and 6x + 3y = v ⇒ 6x + 3y - v =0
On comparing, we get,
Substitute the values in condition for no solution , we get ,
Consider second and third ratio, we get,
Solve for v , we get,
Thus, for all values v except v = 12
The system will have no solution
at v = 12 the system will have infinite many solution.
Thus, option (a), (b) , (c) , (d) are correct.