SCIENCE HELP If you are applying a force to an object and another person is applying another force to the object what is going to happen to the object? Construct your hypothesis using an “If…, then…” statement.

Answers

Answer 1

Answer:

if the vector sum of the force applied by you and the force applied by another person is zero, then the object will not accelerate since the net force on the object is zero in this case. hence the object will not move at all or if it was already moving , will move at constant velocity.

if the vector sum of the force applied by you and the force applied by another person is non-zero, then the object will not accelerate since there is net force on the object in this case. hence the object will accelerate.

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Someone please help me

How much work is done in the vertical direction if 125 N of force is needed to hold an object at shoulder height as a person walks 2 m forward

Answers

Work is the product of force multiplied by the distance moved, but since the distance moved in the vertical direction is zero

Work Done = 0 joules

Given data

Force = 125N

Horizontal Distance = 2 m

Vertical distance = 0 m

Formula for work

Work = Force * Distance

Solution

substitute the given information

Work Done in the horizontal direction= 125*2

Work Done = 250 Joules

Learn more about work here:

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A 10,000-kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 20,000 kg. The cars become coupled and continue traveling. Calculate the final velocity of the cars.

Answers

Answer:

10 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following

$p_i = p_f$

$m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v$

where

$m_1 = 10,000 kg$ is the mass of the first car

$u_1=30 m/s$ is the initial velocity of the first car

$m_2 = 20,000 kg$ is the mass of the second car

$u_2 = 0$ is the initial velocity of the second car

$v$ is the final velocity of the two combined cars after the collision

Re-arranging the equation and substituting the numbers, we find

$v=(m_1 u_1 +m_2 u_2)/(m_1+m_2)=((10,000)(30)-0)/(10,000+20,000)=10 m/s$

A person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.A) What is her average speed over the entire trip?B) What is her average velocity over the entire trip?

Answers

Answer:

A.) 3.975 m/s

B.) 0.925 m/s

Explanation:

Given that a person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.

A) What is her average speed over the entire trip?

The average speed = (4.90 + 3.05)/2

Average speed = 7.95/2

Average speed = 3.975 m/s

B) What is her average velocity over the entire trip?

Since velocity is a vector quantity, that is, we consider both the magnitude and direction

Average velocity = ( 4.90 - 3.05)/2

Average velocity = 1.85/2

Average velocity = 0.925 m/s

What is the equation for calculating electric power?

Answers

Power consumed by an electric device, or dissipated as heat, is

Power = (voltage between the ends of the device) x (current through it)

The equation for calculating electric power is given by the folloowing equation : -

P = VI

Where P stands for power, V for potential difference and I for current.

In a voltaic cell electrons flow from the anode to the cathode. true or false

Answers

True , In a voltaic cell, the anode is the electrode where oxidation occurs and electrons are produced. The cathode is the electrode where reduction occurs and electrons are consumed.

The electrons flow from the anode to the cathode through an external circuit, which generates an electric current. This flow of electrons is what produces the electrical energy in the cell.

In a voltaic cell, also known as a galvanic cell, a spontaneous redox reaction occurs, which results in the conversion of chemical energy into electrical energy. This redox reaction involves the transfer of electrons from one substance to another.

The electrons produced at the anode flow through the external circuit to the cathode. This flow of electrons is driven by the difference in electric potential between the anode and the cathode.

This potential difference is often referred to as the cell voltage or electromotive force (EMF) of the cell.

As the electrons flow through the external circuit, they produce an electric current, which can be used to power electrical devices.

Meanwhile, the redox reaction continues within the cell, with electrons being transferred from the anode to the cathode via an ionic bridge or salt bridge, which allows the movement of ions between the two half-cells to maintain charge neutrality.

Overall, the flow of electrons from the anode to the cathode through the external circuit is what produces the electrical energy in a voltaic cell.

To know more about electrons refer here

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a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

The expression for the bullet's speed vbullet is $v=\sqrt{(2\mu_k (m+M)gd)/(m)}$ and the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

$K_i = (1)/(2)mv^2$

where

m is the mass of the bullet

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

$F=\mu_k (m+M) g$

where

$\mu_k$ is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

$W=-Fd = -\mu_k (m+M)g d$

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

$W=K_f - K_i = -K_i$

And so

$-\mu_k (m+M) g d = -(1)/(2)mv^2$

By solving for v, the solution for the bullet speed:

$-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}$

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, $\mu_k = 0.20$