PHYSICS HIGH SCHOOL

When magnesium (Mg2+) and fluorine (F1-) combine in an ionic bond, the resulting formula will be A) Mg2F.


B) Mg2F2.


C) MgF.


D) MgF2.

Answers

Answer 1
Answer:

Answer is: D) MgF₂.

Magnesium fluoride is salt, ionic compound.

1) Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

2) Fluorine (F) is nonmetal with greatest electronegativity, which meand it easily gain electrons.

Fluorine jas atomic number 9, which means it has 9 protons and 9 electrons. It gain one electron to form fluorine anion (F⁻) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of fluorine ion: ₉F⁻ 1s² 2s² 2p⁶.
Answer 2
Answer: The fluorine has one spare electron per atom and the magnesium has a need for 2. This means for one magnesium you need two fluorine atoms making the formula MgF2.

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A 30cm diameter wheel rotates with a constant angular acceleration of 2.00 rad/s2. It starts from rest at t = 0, and a chalk line drawn to a point, P, on the rim of the wheel makes an angle of 37.1° with the horizontal at this time. At t = 2.00 s, find (a) the angular speed of the wheel (b) the linear velocity and tangential acceleration of P

Answers

Answer:

a) 4.00 rad/s

b) 0.6 m/s, 0.3 m/s²

Explanation:

Given:

ω₀ = 0 rad/s

α = 2.00 rad/s²

t = 2.00 s

Find:

a) ω

b) v, a

a) ω = αt + ω₀

ω = (2.00 rad/s²) (2.00 s) + (0 rad/s)

ω = 4.00 rad/s

b) v = ωr

v = (4.00 rad/s) (0.15 m)

v = 0.6 m/s

a = αr

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Kelly carried a box weighing 10 N the 200 meters from his car to his new house.  George took the box from Kelly and carried it up the 3 meter tall flight of stairs.  Who did more work?

Answers

While moving box from car to house
W = F * d * cosine (90 degree)
= 10N * 200m * 0 
= 0Nm

While lifing 3m tall flight of stairs
W=F*d*cosine(0 degree)
= 10N * 3m
= 300 Nm

George did more work

I think George did more work because George moved the box to the same direction as the force that he applied. So he is applying an upward force to the box to keep it from falling down and moving to the box up the stairs and Kelly does move the box farther than George, but he isn´t doing any work before the force he applies to the box on a different direction than movement.


Hope this helps


Tobey

While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the speed of the tennis ball is

Answers


Well, you see, I don't think Alana really is the reference frame. 
Call me paranoid, but I think you changed the reference frame
during the question, and didn't tell us.

In which reference frame is the 19 km/hr measured ?
It CAN'T be Alana's reference frame.  Your own reference
frame moves along with you, and you can't move in it, even
if your name is Alana.

If Alana is the reference frame, and she throws the tennis ball
at 11 km/hr, then the speed of the ball is 11 km/hr in Alana's
reference frame.  Her reference frame moves with  her, so
it makes no difference how fast she is skateboarding in any
other reference frame, who she throws the ball at, or whether
or not he sees it coming and catches it.

Yes, this stuff can get confusing.  And if you think it's bad now,
wait till you start reading some of Prof. Einstein's stuff, where
two people in the same reference frame can watch the same
tennis ball, and not even agree on how fast it's moving, because
THEY're both moving and their own motion makes their rulers
and clocks change !  So they measure different speeds, and
they're both right !

But I got distracted.  I'm sorry.  The point I'm trying to make,
right now when you're just starting to learn reference frames,
is that EVERY time you say a speed, you have to tell which
reference frame the speed is in.  Because, as you're starting
to learn, the same object can have a different speed in every
reference frame.

And, just in case you're thinking about this later today
and you want to ask "Which one is the REAL speed  ?" . . .
THAT's the whole point of learning about reference frames !
There is NO SUCH THING as REAL speed.  It ALWAYS
depends on which reference frame it's measured in.  They're
all different, they're all real, and they're all correct.

The first thing we must do for this case is to define a frame of reference.

We know that, the frame of reference for this case is Alana.

Therefore, the tennis ball has a speed relative to Alana.

The speed relative to Alana, is the same speed with which Alana throws the tennis ball.

Therefore, the speed of the tennis ball is:

v = 11 Km/h

Answer:

The speed of the tennis ball is:

v = 11 Km/h

If a car goes five times as fast how much more kinetic energy will it have?

Answers


For that answer, we should take a second to look at the formula for kinetic energy:

                Kinetic Energy of an object = (mass) x (speed)² .

The important thing to notice is that the KE is proportional to the square of
the speed. So if you multiply the speed by some number, the KE changes
by the square of that number.

Multiplying the speed of the car by 5 gives it (5)² = 25 times as much KE.
the care will have 25 times as much kinetic energy as before

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Answers

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Answers

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