Answer: A yo-yo in someone's hand
Explanation:
Potential energy is the energy possessed by a body due to virtue of its position. Kinetic energy is the energy possessed by the body due to virtue of its motion.
A swimmer kicking their legs, a car driving on the road, an arrow flying at a target possess kinetic energy because of their motion. A yo-yo in someone's hand possess elastic potential energy.
Answer:
The answer is D
Explanation:
just trust
cooled air
I also think it's hot air, but I'm pretty sure it's because hot air rises. I'm not 100% sure so I'm sorry if it wrong :)
Answer:
Plasma
Explanation:
Plasmais the most common because plasma is a gas that has been energized to the point that some of the electrons break
With what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss the rock?
Answer in units of $m / s$.
Answer:
To solve this problem, we can use the kinematic equation for horizontal motion, which relates the initial velocity ($v_{0}$), final velocity ($v_{f}$), acceleration ($a$), and displacement ($d$) of an object:
$d = v_{0} t + \frac{1}{2}at^{2}$
In this case, we want to find the minimum initial velocity ($v_{0}$) that the divers must have to clear the rock. To do this, we can assume that the divers just graze the rock at the start of their trajectory, so the displacement in the horizontal direction is equal to the distance from the cliff to the rock ($d = 9.34 m$). We also know that the acceleration in the horizontal direction is zero, so the only force acting on the divers is gravity in the vertical direction, which gives an acceleration of $a = 9.8 m/s^{2}$.
At the instant the divers leave the cliff, they have zero horizontal velocity, so $v_{0} = 0$. We can use the equation above to solve for the time it takes for the divers to fall from the cliff to the level of the rock:
$d = \frac{1}{2}at^{2} \Rightarrow t = \sqrt{\frac{2d}{a}}$
Plugging in the numbers, we get:
$t = \sqrt{\frac{2(9.34 m)}{9.8 m/s^{2}}} \approx 1.44 s$
Since the cliff divers want to clear the rock, they need to travel a horizontal distance of at least $9.34 m$ during this time. We can use the equation for horizontal motion again to solve for the minimum initial velocity:
$d = v_{0}t \Rightarrow v_{0} = \frac{d}{t} = \frac{9.34 m}{1.44 s} \approx 6.49 m/s$
Therefore, the minimum horizontal velocity that the cliff divers must have to clear the rock is approximately $6.49 m/s$.
been transmitted.
bounced off .
been absorbed
Correct answer choice is :
C) Bounced off
Explanation:
Reflection is the difference in the path of a wavefront at an interface within two various media so that the wavefront returns into the tool from which it began. Current models involve the reflection of light, sound and water waves. Reflection is when light bounces off an object. If the cover is soft and shiny, like glass, water or bright metal, the light will reflect at the same point as it hit the cover.