The volume of a greenhous is 150 feet long, 20 feet wide, 10 feet high at the sides, and the 15 feet high in the center what is the cubic feet?

Answers

Answer 1

Answer: long=150
wide=20
high=10
volume=l*w*h
=150*20*10=30000which will be divided by 15 to get the cubic feet.
The answer will be 2000.

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What is the range of the data set?0|1 4 4 1|1 2 7 2|0 3|5 5 4|8 Key: 3|5 means 35

If t = 10m + 40 models this scenario,t = total cost;
m = number of months;

Which of the following statements is true?

O A. The total cost will increase by $40 for every 10 months that pass.
B. The total cost will increase by $10 for every 40 months that pass.
C. The total cost will increase by $10 for every month that passes.
D. The total cost will increase by $40 for every month that passes.

Answers

The answer is d ...........................

Choose the correct simplification of the expression (3x − 6)(2x2 − 4x − 5).6x3 − 24x2 + 9x − 30
6x3 + 9x + 30
6x3 − 24x2 + 9x + 30
6x3 − 24x2 + 39x + 30

Answers

Answer:

Option 3rd is correct

$6x^3-24x^2+9x+30$

Step-by-step explanation:

Given the expression:

$(3x-6)(2x^2-4x-5)$

Multiply the first term of the first expression with second expression and second term of the first expression with second expression we have;

$3x(2x^2-4x-5)-6(2x^2-4x-5)$

using distributive property we have;

$6x^3-12x^2-15x-12x^2+24x+30$

Combine like terms we have;

$6x^3-24x^2+9x+30$

therefore, the correct simplification of the given expression is, $6x^3-24x^2+9x+30$

The answer is C: 6x^3 - 24x^2 + 9x + 30

jenna''s sixth-grade class is taking a bus to the zoo. the zoo is 156 miles from the school. if the bus travels an average of 55 mi/h, how many seconds will it take to get to the zoo?

Answers

$V=(s)/(t),\ \ \ \ \ \ \ V-speed,\ s-distance,\ t-time\nt=(s)/(V)\n\nt=(156)/(55)=2,84h=170,4s$

it will take Jenna's class about 3 hours to arrive to the zoo

Find the unknown side length, x. Write your answer in simplest radical form. A. 15 B. 11 square root 2 C. 2 square root 121 D. 15 square root 5

Answers

We have two right isosceles triangles. Hypotenuse of that triangle is a $√(2)$ or you can use the Pythagorean theorem: 11² + 11² = c²
121 + 121 = c²
242 =c² c= $√(242)= √(121*2)=11 √(2)$ Answer is the same: B) 11 square root 2

Answer:

Step-by-step explanation:

6358 was rounded to the nearest one.

What is the lower bound?

Answers

The lower bound of the number 6358 when rounded to the nearest one (nearest whole number) remains 6358 since it is already a whole number.

Rounding a number to the nearest one implies that we are rounding it to the nearest whole number or integer. In this case, the number 6358 was rounded to the nearest whole number, which means we want to find the lower bound of this rounded value.

When we round 6358 to the nearest whole number, we find that it becomes 6358 itself because it is already a whole number. Therefore, the lower bound of the rounded value is the same as the original value, which is 6358.

In summary, when 6358 is rounded to the nearest one (nearest whole number or integer), the lower bound of the rounded value is also 6358 because the original number is already a whole number. There is no change in the value when rounding to the nearest one in this case.

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3 is the lowest in that bound

Read the real-world situation and substitute in values for the projectile motion formula. Then solve the resulting quadratic equation by factoring to answer the question. An airplane pilot jumps out of an airplane and has an initial velocity of 60 feet per second downwards. How long does it take to fall from 1000 feet to 900 feet before the parachute opens? The pilot falls for seconds before the parachute opens.

Answers

Solving quadratic equation 16 t² -60t -100=0 formed by Projectile Motion Formula and given conditions it is found that it takes t = 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.

What is a quadratic equation?

Quadratic equation is an equation which contains one unknown variable and the highest power of this unknown variable is 2. Let x be the unknown variable then the standard quadratic equation in x is given by

ax²+bx+c =0, where a, b, c are constants and a≠0

We can solve this equation by factorizing ax²+bx+c and putting those factors equal to zero to solve for x.

Projectile Motion Formula h = -16 t² + v t + s,

where t = time in seconds

h = height of the projectile

v = initial velocity

s= starting height of fall

Given s = 1000 feet, v= 60 feet per second, h = 900 ft

And t we have to find.

Projectile motion equation becomes:

900 = -16 t² + 60 t + 1000

⇒16 t² -60t + 900-1000=0