How do you do zero pairs

Answers

Answer 1

Answer: Zero pairs are basically 2 numbers that add up to zero like -1 +1 = 0 they cancel each other out. By assigning tiles to represent each number, you can cancel out the zero pairs and the remaining tiles will represent the sum or difference of the numbers.

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Describe the rule of this function, and find the missing number8-->15
6-->11
10-->19
4-->?

Answers

-2,+4. If you put them in order, they will be simpler
4->?
6->11
8->15
10->19
so it is 4-->7

Round 38.49 to the nearest whole number

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38. The nearest whole number to 38.49 is 38 because at .5 you begin rounding up to the nearest whole number.

4/9x + 1/5x=58 i need help solving this equation

Answers

So first let’s combine like terms and add 4/9x and 1/5x together to get 29/45x =58. Next, multiply 58 by 45/29 to isolate x, so x=90

P( total shown=3) rolling two fair number cubes

Answers

Dice have six sides. So 6 cubed would be 216. Does that sound right?

PLSSSS HELP ITS DUE TODAY!!!!!

Answers

Answer:

Both Jules' and Lauren's equations are correct because they have slopes that are the negative reciprocal of the slope of the given line, making them perpendicular to the given line.

Step-by-step explanation:

Let's reevaluate the equations based on the corrected given line equation:

$\sf y - 2 = (1)/(5)(x - 3)$

The given line equation is in point-slope form: $\sf \boxed{\sf y - y_1 = m(x - x_1)}$ , where m is the slope.

Given line equation: $\sf y - 2 = (1)/(5)(x - 3)$

While comparing, we get

$\textsf{The\underline{ slope (m) }of the given line is }(1)/(5)$

For a line to be perpendicular to the given line, its slope must be the negative reciprocal of the slope of the given line.

The negative reciprocal of $\sf (1)/(5)$ is $\sf -5.$

Now let's check the slopes of the equations provided by Jules and Lauren:

1. Jules' equation: $\sf y = -5x + 1$

The slope of Jules' equation is -5, which matches the negative reciprocal of the slope of the given line.

2. Lauren's equation: $\sf y = -5x + 7$

The slope of Lauren's equation is also -5, which again matches the negative reciprocal of the slope of the given line.

Both Jules' and Lauren's equations have a slope of -5, which is the negative reciprocal of the slope of the given line $(1)/(5)$ .

Therefore, both equations are correct and satisfy the condition of being perpendicular to the given line $\sf y - 2 = (1)/(5)(x - 3)$

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$y-2=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{5}}(x-3)\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\n \cline{1-1} \n y-y_1=m(x-x_1) \n\n \cline{1-1} \end{array} \n\n[-0.35em] ~\dotfill$

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{1}{5}} ~\hfill \stackrel{reciprocal}{\cfrac{5}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{5}{1} \implies -5}}$

so ANY line that is perpendicular to that equation above, will have a slope of -5, so any of these are all perpendicular to it

$\begin{array}{llll} \stackrel{ Jules }{y=-5x+1} \n\n\n \stackrel{ Lauren }{y=-5x+7} \n\n\n y=-5x+999999999 \n\n\n y=-5x-93789 \end{array}\hspace{5em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\n \cline{1-1} \n y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \n\n \cline{1-1} \end{array}$

What is 4,720 round to the nearest thousand

Answers

The answer would be 5,000

5,000 because 720 rounds to 1,000 and so that is the zeroes for 5,000 and it makes sense.

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