MATHEMATICS HIGH SCHOOL

A cube-shaped box has a volume of 125 cubic inches. If the box is packed full of cubes with edge lengths of 1 inch, how many cubes can fit along one face of the box?

Answers

Answer 1

Answer:

25 cubes can fit along one face of the box.

What is the volume of the cube?

The volume of a cube is equal to the product of the length, width, and height of a cube.

Given that a cube-shaped box has a volume of 125 cubic inches

If the box is packed full of cubes with edge lengths of 1 inch,

So the volume of each cube is 1 cubic inch because the length and width, and height of each cube are 1 so 1 inch × 1 inch × 1 inch= 1 cubic inch

Since the box has a volume of 125 cubic inches, then exactly 125 cubes can fit in the box.

125 x 1 inch³ = 125 inch³

Each side has a length of 4 cubes. 5x5x5 =125.

One side would have an area of 16 because there are 5 across and 5 in height.

⇒ 5×5×1 = 25 cubic squares.

So the number that can fit along one side of the box would be 25

Hence, 25 cubes can fit along one face of the box.

Learn more about the cube here:

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Answer 2

Answer:

Answer:25

Step-by-step explanation:

Square cube of 125 is 5. If you want 1 side it’s gonna be 5 to the second power which is 25

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Answers

Answer:

x=5

Step-by-step explanation:

7x-5=4x+10

3x-5=10

3x=15

x=5

Which function describes the graph in the picture? NEED HELP ASAP

Answers

-- The function is a sine or cosine that wiggles from 3 below to 3 above its average value. So the amplitude is 3 . That lets out the 1st and 3rd choices.
It has to be the 2nd or 4th choice.

Looking at the graph, the y-intercept is at y=6.
The y-intercept is the point where x=0, so f(0)=6.

Test the 2nd choice: f(x) = 3 cos(x) + 3

   f(0) = 3 cos(0) + 3

cos(0) = 1 so f(0) = 3 (1) + 3    = 6

Choice-2 is looking good.
Just to be sure, let's check choice-4:

   f(x) = 3 sin(x) + 3

   f(0) = 3 sin(0) + 3

sin(0) = 0 so    f(0) = 3 (0) + 3    = 3

Beautiful ! Choice-4 flopped. The answer is choice-2 .

Answer: b

Step-by-step explanation:

Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall. Approximately what percent of the adult male population is taller than the average basketball player?0.13%

0.87%

49.87%

99.87%

Answers

Answer: First Option is correct.

Step-by-step explanation:

Since we have given that

Mean $(\mu)$ = 70 inches

Standard deviation $(\sigma)$ = 3 inches

Average basket ball player $(\bar{X})$ = 79 inches

Since it is normally distributed assume with 5% significance .

So, it becomes,

$Z>\frac{\bar{X}-\mu}{\sigma}\n\nZ>(79-70)/(3)\n\nZ>(9)/(3)\n\nZ>3\n\n\therefore\ P(Z>3)=1-0.9987=0.0013$

At 0.05 level of significance , 0.0013 = 0.13% of the adult male population is taller than the average basketball player .

Hence, First Option is correct.

Kindly check this link for more details:

Therefore the answer is 0.13% is the approximate percentae of the adult male population who are taller than the average basketball player

Screen measures 30 cm wide n 22 cm high what is the diagonal measure of the screen

Answers

I think you'd use the pythagoran theorem for this (a squared + b squared = c squared). So 30 squared plus 22 squared equals the diagonal measure squared. This is 900 + 484 = c squared. That's 1384. The square root of that is 37.

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