What is (in fractions) 27- 25 1/6 (don't need explanation)

Answers

Answer 1

Answer: 27-25 1/6= 13/6 (thing wouldn't let me post without 20 characters)

10,000

Sue And Juanita Were Biking On The Track Around Their Town Park. Sue Started First. When She Had Biked 9 Laps, Juanita Had Biked 3 Laps. When Juanita Had completed 12 laps, Sue had completed 30 laps. did both rates remain steady

Answers

Answer:

No. Both rates did not remain steady.

Step-by-step explanation:

When Sue had biked 9 laps, Juanita had biked 3 laps. This means that Juanita's rate is 3 laps for every 9 laps Sue bikes.

When Juanita had completed 12 laps, Sue had completed 30 laps. This implies that Sue's rate is 30 laps for every 12 laps Juanita bikes.

In conclusion, the rates did not remain steady because Sue's rate was significantly faster than Juanita's.

No both rates did not remain steady

Select Is a Function or Is not a Function to correctly classify each relation. Title Is a Function Is not a Function {(2, 2),(4, 4),(6, 6),(8, 8)}
{(0, 3),(3, 5),(5, 6),(8, 4)}
{(1, 2),(3, 3),(4, 8),(6, 3)}
{(3, 4),(5, 2),(5, 6),(7, 3)}

Answers

A mapping is said to be function if each element in the domain is related with only one element in the range.Or you can say that a relation is a function also when two different elements in domain have same image or related with same element of the Co domain.

The elements which is related with elements of domain is called Co domain.

So , using the definition of function that i have written above you can classify that the relation is a function or not

1. {(2, 2),(4, 4),(6, 6),(8, 8)}

→→Each element is related with itself , no two different images have different Preimage, For example (2,3),(2,4) that is not happening in this case. so this relation is a function.This kind of function is called identity function.

2. (0, 3),(3, 5),(5, 6),(8, 4)→Different element have different images .So this Relation is a function.

3. (1, 2),(3, 3),(4, 8),(6, 3) →→→Here two elements have same image 3. But still this is a function because two elements in domain or preimage can have same image in a function.

4. (3, 4),(5, 2),(5, 6),(7, 3)→→→This is not a function because two different elements of image have same preimage that is image of 2,and 6 have same preimage which is 5. So this is not a function.

From The given options 1,2,3 are functions.

{(2, 2),(4, 4),(6, 6),(8, 8)} Is a function.
{(0, 3),(3, 5),(5, 6),(8, 4)} Is a function.
{(1, 2),(3, 3),(4, 8),(6, 3)} Is a function.
{(3, 4),(5, 2),(5, 6),(7, 3)} Is not a function.

For a relation to be a function, every x value must have only one y value.

Hope this helps.

Other Questions

Omar shaded a model to show the part of the lawn that he finished mowing. What fraction names the shaded parts ( 8 eighths with 1 shaded ) EXPLAIN how you know how to write the faction

Fish 1 swims 4 feet in 2 seconds, Fish 2 swims 9 feet in 3 seconds, and Fish 3 swims 12 feet in 6 seconds. Use the table above to determine which fish are swimming at the same speed.

Between 2000 and 2014, the number of twin births in a certain country increased by 15%, to approximately 133975. About how many twin births were there in 2000?

What expression can be used for estimating 868 divided by 28

What is (in fractions) 27- 25 1/6 (don't need explanation)

Answers

Related Questions

Answers

Answers

Answers

Answers

10,000

Answers

Answers