There are total of pet fish and reptiles in the United States.
Calculations that include changeable altering multipliers, joining, removal, and random subdivision must be done. They could accomplish the following if they united: An algorithm, some data, and a mathematical problem.
To find the total number of pet fish and reptiles in the United States, we simply need to add the number of pet fish and pet reptiles together:
Total =
To add these numbers together, we need to express them using the same power of 10. We can do this by rewriting 9.4 * 10^6 as 0.94 * 10^7:
Total =
Now, we can add the numbers together:
Total =
= (since )
=
Therefore, there are a total of pet fish and reptiles in the United States.
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Therefore , the solution of the given problem of expressions comes out to be the total number of pet fish and reptiles in the US is roughly
1.494 * 10⁸.
It is necessary to perform calculations which it involve joining, removal, and random subdivision variable changing multipliers. If they banded together, they could do the following: A mathematical challenge, some information, and an algorithm. A statement of equation truth contains formulas, elements, and arithmetic procedures like additions, subtractions, errors, and groupings. It is possible to assess and analyse words and phrases.
Here,
The number of fish and reptiles kept as pets must be added to the overall number of pets:
=> 1.4 * 10⁸ + 9.4 * 10⁶
We must change these numbers to the same power of 10 in order to add them. Since 108 is equal to 100 million,
we can achieve this by moving the decimal point in the second figure two places to the right:
=> 1.4 * 10⁸ + 0.094 * 10⁸
We can now multiply the numbers:
=> 1.494 * 10⁸
Thus, the total number of pet fish and reptiles in the US is roughly
=> 1.494 * 10⁸.
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20x + 25y = 345
How much more can Paul shovel in 1 minute than Melinda?
3 square feet per minute
6 square feet per minute
9 square feet per minute
15 square feet per minute
Answer: Hello mate!
we have the system of equations
30x + 30y = 450
20x + 25y = 345
where x is the number of square feet of snow that Melinda shovels in one minute, and y is the number of square feet of snow that Paul shovels in one minute.
Let's solve the system of equations, first, isolate one of the therms in the first equation, for example, x.
30x+30y = 450
x + y = 450/30 = 15
x = 15 - y
now we can replace it in the second equation and solve it for y.
20x + 25y = 345
20(15 - y) + 25y = 345
300 - 20y + 25y = 345
5y = 45
y = 45/5 = 9
Paul can shovel 9 square feets of snow in one minute, now replace it in the first equation and solve it for x.
x + y = 450/30 = 15
x + 9 = 15
x = 15 - 9 = 6
so melinda sholves 6 square feet of snow in one minute.
The question is:
How much more can Paul shovel in 1 minute than Melinda?
We need to see the difference y - x = 9 - 6 = 3
this means that paul shovels 3 more square feet per minute than Melinda.