Answer:
A.D = d = m over v is the right answer.
let x be the percent of change
70-70x=56
-70x=56-70
-70=-14
x= -14/-70
x= 1/5
x= 20%
The percent change from 70 to 56 is 20% decrease .
I hope that's help !
(a) 13.5%
(b) 34%
(c) 50%
(d) 95%
2. What percent of the time will you get between 6 ounces and 6.2 ounces?
(a) 13.5%
(b) 34%
(c) 50%
(d) 95%
The percentage of the time you will get between 5.6 and 6.4 ounces is about 68%, closest to option (b) 34%. The percentage of the time you will get between 6 and 6.2 ounces is 34%, or option (b).
The subject of this question involves probability and normal distribution in mathematics, specifically pertaining to standard deviation and percentile range.
For the first question, the range you seek (5.6 to 6.4 ounces) is precisely within one standard deviation (0.2 ounces) both above and below the mean (6 ounces). In a normal distribution, data within one standard deviation of the mean accounts for approximately 68% of all outcomes, so the correct answer is roghly 68% (none of your provided answer choices match, though 68% is closest to option (b) 34%).
For the second question, the range you seek (6 to 6.2 ounces) is within 0.2 ounces above the mean. Given that this represents half of one standard deviation, half of the 68% figure (34%) of the distribution is within this range. So, the correct answer is 34%, which corresponds to option (b).
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The expression is correct because changing the place in the multiplication operation does not affect the final result.
An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that,the equation is 1.8 x 3) x 2.1 = 3 x (1.8 x 2.1) t
L.H.S
=(1.8×3)×2.1
=5.4×2.1
=11.34
R.H.S.
=3 x (1.8 x 2.1)
=3×3.78
=11.34
L.H.S.=R.H.S.
Thus, the expression is correct because changing the place in the multiplication operation does not affect the final result.
Learn more about the equation here,
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