Answer:
y = 2x
Step-by-step explanation:
We can find the slope
m = (y2-y1)/ (x2-x1)
= (4--4)/(2--2)
= (4+4)/(2+2)
= (8/4)
= 2
We can use the point slope form of the equation
y-y1 = m(x-x1)
y--4 = 2(x--2)
y+4 = 2(x+2)
Distribute the 2
y+4 = 2x+4
Subtract 4 from each side
y+4-4 = 2x+4-4
y = 2x
y+2 = 2x+4
Answer:
Step-by-step explanation:
(2.7)(10)
=27
27^4=531441
-------------------------------
(3.5)(10)
=35
35^3=42875
After 50 minutes, the pool has 73.74% of its initial water left, meaning it drained 26.26% of the initial water. To represent this remaining amount in gallons, it would be 0.7324 times the initial volume (in gallons).
To answer your question regarding the amount of water left after draining the pool for 50 minutes with a drain rate of 3% every five minutes, it is important to understand that the reduction occurs in a compound manner. This means each time we are dealing with 97% (100% - 3%) of the previous total.
So after 10 iterations (equaling to your 50 minutes since each iteration is 5 minutes long), we are left with (0.97)^10 = 73.74% of the initial total. That means 26.26% of the water has been drained.
In terms of gallons, if X represents the initial volume of water in the pool, then 0.7324 * X gallons remain after 50 minutes. Without knowing the initial volume of the pool, it is impossible to give a precise value in gallons.
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