for #1 it is y=-3/2x+4 the -3/2 is the slope and the 4 is the y intercept
for #2 it is y=6/+2 the 6/2 is the slope and the 2 is the y-intercept
the y-intercept is where the line passes through the y axis
object is 10 m/s. If the force is changed to 90 N, what will be the acceleration of the object?
Answer:
acceleration would be 9 meters per second squared
Step-by-step explanation:
If quantity "A" varies directly with quantity "B", then we can write:
A = kB
Now, this problem says that force (f) varies directly with acceleration (a). So we can write:
f = ka
Given f = 100 and a = 10, so we substitute and find k (the proportionality constant). Shown below:
f = ka
100 = k(10)
k = 100/10
k = 10
So, we have
f = 10a
Now, force is 90, so what's the acceleration?
90 = 10a
a = 90/10
a = 9
So, the acceleration would be 9 meters per second squared
Answer:
the answer is D.106.3in^3
Step-by-step explanation:
i know this
Use the dimensions you calculated in part (a) to find the area of the lawn.
What are the answers and how do i solve it thank you
Answer:
Dimensions, Length = 85 feet and Width = 40 feet
Area of lawn = 3400
Step-by-step explanation:
Given: Lawn is rectangular in shape
Length of lawn is 5 feet more than twice its breath/width
Perimeter of Lawn = 250 feet
To find: (a) Length and width of lawn
(b) Area of Lawn
First let the a variable for width/breadth. Say, Width = b.
So, the length of lawn = 2b + 5
Perimeter of Rectangle = 2 × ( length + width )
Now, substitue given values in this formula
∴ Perimeter of Lawn = 2 × ( 2b + 5 + b )
∴width = 40 feet
⇒ length = 85 feet
Now we find are of lawn using formula of area of rectangle
Area of lawn = length × width
= 85 × 40
= 3400
Dimensions, Length = 85 feet and Width = 40 feet
Area of lawn = 3400