Transforme 0,4m em mm

Answers

Answer 1
Answer: 1m = 1000 mm

0,4m = 0,4 * 1000 = 400mm

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Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27 and 6.35 g/cm3, respectively, and their respective atomic weights are 61.4 and 125.7 g/mol, determine whether the crystal structure for this alloy is simple cubic, face-centered cubic, or body-centered cubic. Assume a unit cell edge length of 0.395 nm.

Answers

The number of atoms in the unit cell of hypothetical alloy composed of metal A and B is 2 so the crystal structure is body-centered cubic.

What is crystal structure?

The crystal structure is the order of the atom arrangement in a repeating way. types of crystal structure are-

  • Simple cubic-In this arrangement, one atom is placed at each corner of the unit cell.
  • Face-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at each face of the unit cell.
  • Body-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at center of the unit cell.

Number of atom can be find out with the following formula,

n=(N\rho)/(m)[\tex]</p><p>Here, (m) is the <strong>mass </strong>of the object and (N) is <strong>Avogadro's </strong>number.</p><p></p><p><strong>Given information-</strong></p><p><strong>Hypothetical alloy </strong>is composed with metal <strong>A</strong> of 12.5 wt%.</p><p><strong>Hypothetical alloy </strong>is composed with metal <strong>B</strong> of 87.5 wt%.</p><p><strong>Densities </strong>of metals <strong>A </strong>and <strong>B</strong> are 4.27 and 6.35 g/cm 3,</p><p><strong>Atomic </strong>weights of <strong>A</strong> and <strong>B</strong> are 61.4<strong></strong>and 125.7 g/mol,</p><p></p><p>The <strong>density </strong>of the alloy is,</p><p>[tex]\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100=5.98[\tex]</p><p></p><p>Similarly the <strong>mass </strong>of the alloy is,</p><p>[tex]m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100=111.15[\tex]</p><p></p><p>As the <strong>mass </strong>and the <strong>density </strong>of the alloy has been obtained and the Avogadro's number is 6.023*10²³.</p><p></p><p>Put the value in the above equation to find the <strong>number </strong>of <strong>atom</strong>, we get,</p><p>[tex]n=2

Thus the number of atoms in the unit cell is 2. The crystal structure is body-centered cubic.

Learn more about the crystal structure here;

brainly.com/question/10816130

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n*(m)/(V_(c)* N_(A))

n=(\rho*V_(c)* N)/(m)....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100

\rho=5.98

We calculate the mass of the alloy

m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100

m=111.15

Put the value into the equation (I)

n=(5.9855*(0.395*10^(-9)*10^(2))^3*6.023*10^(23))/(111.15)

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

True or false?A bomb dropped from an airplane and a ball thrown at a particular angle are examples of projectile motion.

Answers

Answer:

True

Explanation:

True hope this helps

True that the answer

The alpha particles leave visible tracks in the cloud chamber becauseIonization by the alpha particle seeds the formation of clouds where the particle has passed.
The kinetic energy of the alpha particles heats the air.
The alpha particle is so energetic that it leaves a smoke trail behind.
The alpha particle strikes nitrogen molecules and breaks them into atomic nitrogen.

Answers

Answer: Ionization  by the alpha particle seeds the formation of clouds where the particle has passed.

The inner atmosphere of a cloud chamber is composed of an easily ionizable gas, this means that little energy is required to extract an electron from an atom. This gas is maintained in the supercooling state, so that a minimum disturbance is enough to condense it in the same way as the water is frozen.  

Then, when a charged particle with enough energy interacts with this gas, it ionizes it.  

This is how alpha particles are able to ionize some atoms of the gas contained inside the chamber when they cross the cloud chamber.

These ionized atoms increase the surface tension of the gas around it allowing it to immediately congregate and condense, making it easily distinguishable inside the chamber like a small cloud. In this way, it is perfectly observable the path the individual particles have traveled, simply by observing the cloud traces left in the condensed gas.  

Why would you expect sodium (Na) to react strongly with chlorine (Cl)?1. They both need to lose one electron.
2. They both need to gain one electron.
3. Sodium needs to lose one electron, and chlorine needs to gain one electron.
4. Sodium needs to gain one electron, and chlorine needs to lose one electron.

Answers

Answer: The correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".

Explanation :

The electronic configuration of sodium (Na) is 1s^2\ 2s^2\ 2p^6\ 3s^1. It has only one vacant electron.

While the electronic configuration of chlorine is 1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^5. It has seven valance electrons.

When Na reacts with Cl, Na will lose one electron and this lost electron gets transferred to chlorine. This forms a strong ionic bond.

So, the correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".

3. is the answer, Sodium needs to lose one electron, and chlorine needs to gain one electron. This is because Sodium's row always wants to give away an electron, while Chlorine's row wants to gain an electron.

The temperature of 20 liters of helium gas is increased from 100°K to 300°K. If the pressure was kept constant, the new volume will be how many liters? a) 6.7 b) 30 c) 60 d) 120 e) None of these

Answers

Answer:

New volume (V2) = 60 liter

Explanation:

Given:

Amount of helium (V1) = 20 Liter

Temperature (T1) = 100°K

Temperature (T2) = 300°K

Find:

New volume (V2)

Computation:

According to Gas Law:

V1 / T1 = V2 / T2

20 / 100°K = V2 / 300°K

V2 = 60 liter

New volume (V2) = 60 liter

Jake drops a book out of a window from a height of 10 meters. At what velocity does the book hit the ground? Answer choices: A: 7.0Meters/Second B: 10Meters/Second C: 14Meters/Second D: 28Meters/Second

Answers

Jake drops a book out of a window from a height of 10 meters. The velocity does the book hit the ground is 14 m/s. hence option C is correct.  

What is velocity?

Velocity is defined as the pace at which an item changes position while moving in one direction, as seen from a certain point of view and as measured by a specific unit of time. Given that it has both a magnitude and a direction, velocity is a vector quantity.  Velocity measures movement that begins in one location and moves to another location.

We are aware that V=final velocity and V2-U2=2.

U is the initial velocity, and A is the acceleration, and D is the distance, therefore V=14 m/s.

Thus, Jake drops a book out of a window from a height of 10 meters. The velocity does the book hit the ground is 14 m/s. hence option C is correct.  

To learn more about velocity, refer to the link below:

brainly.com/question/18084516

#SPJ2

C is your answer. we know V^2-U^2=2 as where V=final velocity.
U is inital velocity
A= acc.
s= distence
a.t.q
v^2 -o^2 =(2*9.8*1o)
so, V=14 m/s