To change 1.34 kg of ice at 0°C to water, you would need to add approximately 448 kJ of heat.
To calculate the amount of heat needed to convert ice at 0°C to water, we use the formula Q = m * Lf. Where Q is the Heat Transfer, m is the mass of the substance (ice in this case), and Lf is the heat of fusion for ice, which is 334 kJ/kg.
Plugging in the values we have: Q = 1.34 kg * 334 kJ/kg = 447.56 kJ.
Therefore, you would need to add approximately 448 kJ of heat to convert 1.34 kg of ice at 0°C to water at the same temperature.
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The heat required to convert 1.34 kg of ice at 0°C to water at 0°C is approximately 450.24 kJ.
When the substance freezes (changes from liquid to solid), the same amount of energy is released back into the surroundings. When a substance changes its phase (solid to liquid or liquid to gas) at a constant temperature, the heat required for this process is known as the heat of fusion.
For ice at its meltingpoint (0°C), the heat of fusion is approximately 336 kJ/kg. Thus for 1.34 kg of ice, we can calculate the heat required by using the formula below:
Heat = mass × heat of fusion
Heat = 1.34 kg × 336 kJ/kg
Heat = 450.24 kJ.
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The complete question is -
How much heat (in kJ) must be added to 1.34 kg of ice at 0°C to convert it to water at 0°C
(2) CH3CH2CH2CH3
(3) CH3CH2CH2COOH
(4) CH3CH2COOCH3
formula represents a hydrocarbon. Therefore, option (2) is correct.
Hydrocarbons are merely carbon and hydrogen. Aliphatic or aromatic. Aliphatic hydrocarbons are saturated or unsaturated open-chain hydrocarbons.Saturated aliphatic hydrocarbons have single bonds, while unsaturated ones have double or triple bonds.
Aromatic hydrocarbons have alternating double bonds in a ring.Only option 2——is a hydrocarbon. Butane, a saturated aliphatic hydrocarbon, with four carbon and 10 hydrogen atoms.
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