MATHEMATICS MIDDLE SCHOOL

Segment JK is shown. Point J is located at (5,−2). Point K is located at (5,−4)What is the midpoint of segment JK

Answers

Answer 1

Answer: midpoint is (x1+x2 / 2 , y1+y2 /2)
(5+5/2, -2+(-4)/2)
10/2, -6/2
(5,-3) would be the midpoint

Answer 2

Answer:

Answer:

(5, -3)

hope i helped bye

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Find the like terms in the expression y+1.2y+ 1.2z.A. Y and 1.2y
B. 1.2y and 1.2z
C. Y and 1.2z
D. Y, 1.2y, and 1.2z
Simplify 2 + 17x – 5x + 9
A. 19x + 4
B. 12x + 11
C. 22x + 11
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Simplify 3(5y + 6) -4.
A. 11y + 14
B. 11y + 18
C. 15y + 14
D. 15y + 2
Factor 81 – 27p.
A 9(9 – 3p)
B. 27 (3 – p)
C. 27 (54 – p)
D. 27 (p – 3)

Answers

$1.\n\underline{y}+\underline{1.2y}+\underline{1.2z}\to\boxed{y;\ 1.2y;\ 1.2z\to\boxed{D}}$

$2.\n2+17x-5x+9=(17x-5x)+(2+9)=\boxed{12x+11\to\boxed{B}}$

$3.\n3(5y+6)-4=(3)(5y)+(3)(6)-4=15x+18-4=\boxed{15y+14\to\boxed{C}}$

$4.\n81-27p=27\cdot3-27\cdot p=\boxed{27(3-p)\to\boxed{B}}\nbut\n81-27p=9\cdot9-9\cdot3p=\boxed{9(9-3p)\to\boxed{A}}$

Answer:

ABCB

Step-by-step explanation:

Use a unit circle, a 30 degrees - 60 degrees - 90 degrees triangle, and an inverse function to find the degree measure of the angle.angle whose sine is one half

Answers

150 is the answer I don’t think it is right

Answer:

150

Step-by-step explanation:

Please help I only have today to do this type of work and I'm struggling!! Alice, Raul, and Maria are baking cookies together. They need cup of flour and cup of butter to make a dozen cookies. They each brought the ingredients they had at home. Alice brought cups of flour and cup of butter, Raul brought cup of flour and cup of butter, and Maria brought cups of flour and cup of butter. If the students have plenty of the other ingredients they need (sugar, salt, baking soda, etc.), how many whole batches of a dozen cookies can they make?

Answers

Answer is In the Picture

The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown.What is the greatest possible whole-number value of the congruent side lengths?

A.9 cm
B.10 cm
C.14 cm
D.15 cm

Answers

Since 9+9=19<20 and 10+10=20=20, the triangles with sides 9, 9, 20 and 10, 10, 20 cannot exist.

Use the cosine theorem to check which option C or D is true:

$20^2=14^2+14^2-2\cdot 14\cdot 14\cos \theta,\n 400=196+196-392\cos \theta,\n 8=-392\cos \theta,\n \n \cos \theta=-(8)/(392) =-(1)/(49)$ .

You have that cosine of the greatest angle (opposite to the greatest side) is negative, this means that angle is obtuse.

$20^2=15^2+15^2-2\cdot 15\cdot 15\cos \theta,\n 400=225+225-450\cos \theta,\n -50=-450\cos \theta,\n \n \cos \theta=(50)/(450) =(1)/(9)$ .

Here you have that cosine of the greatest angle (opposite to the greatest side) is posiative, this means that angle is acute.

Answer: the greatest possible whole-number value of the congruent side lengths is 14 (choice C)

Answer:

Step-by-step explanation:

It's in the picture ?

Answers

Answer:

4

Step-by-step explanation:

From first piece -6 < x ≤ 0.

From second piece 0 < x ≤ 4.

Therefore -6 < x ≤ 4 → x ∈ (-6, 4]

-7 ∉ (-6, 4]

-6 ∉ (-6, 4]

4 ∈ (-6, 4]

5 ∉ (-6, 4]

What is the volume of a cube with a side length of 11 inches? A. 33 in3 B. 10,648 in3 C. 1331 in3 D. 121 in3

Answers

$s= 11 \ inches \n \nV=s^3 \n \n V=11^3 = 11*11*11 = 1331 \ in^3 \n \n Answer : \ C. 1331 in3$

The volume of a cube is s^3
v=s^3
v=11^3
v=1331

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