The score in the second exam is 94.
Given:
Score in the first exam = 86
Mean score of two exams = 90
We have to find the score of second exam.
Let the score of second exam be x.
We know, mean is given by:
⇒ Mean = (Total score in all the exams) / (Total number of exams)
Here,
Total score in all the exams = 86 + x
Total number of exams = 2
Mean = 90 (given)
⇒ 90 = (86 + x)/2
⇒ 90 × 2 = 86 + x
⇒ 180 = 86 + x
⇒ x = 180 - 86
⇒ x = 94
Therefore, the score in the second exam is 94.
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y = x + 7
Select one:
a. Lines y = −one halfx + 9 and y = x + 7 intersect the x-axis.
b. Lines y = −one halfx + 9 and y = x + 7 intersect the y-axis.
c. Line y = −one halfx + 9 intersects the origin.
d. Line y = −one halfx + 9 intersects line y = x + 7.
Answer:
There will be 24 millimeters in 1/6 of an hour
Step-by-step explanation: because there is an mathematical expression
the rectangle is 142 inches, find the width
and length of the rectangle.
Answer:
35 and 36
Step-by-step explanation:
If the smaller dimension is x, then the larger dimension is x + 1. Therefore:
2x + 2(x + 1) = 142
2x + 2x + 2 = 142
4x = 140
x = 35
One dimension is 35, and the other dimension is 36.
Answer:
The dimensions of the rectangle are 35 inches by 36 inches.
Step-by-step explanation:
If the length and width are consecutive integers and L=n, then W=n+1 assuming the width is larger.
We are given the perimeter is 142 inches so: 2L+2W=142.
Substituting L=n and W=n+1 we have: 2(n)+2(n+1)=142.
Let's solve it:
2(n)+2(n+1)=142
Distribute:
2n+2n+2=142
Combine like terms:
4n+2=142
Subtract 2 on both sides:
4n=140
Divide both sides by 4:
n=140/4
n=35
Since L=n, then the length is 35 inches.
Since W=n+1, then the width is 36 inches.
The dimensions of the rectangle are 35 inches by 36 inches.