Read the picture above to answer. Thanks

Answers

Answer 1

Answer: The answer and explanation is down below. HTH

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Jabari owns 100 shares of Stock A and 45 shares of Stock B. For the past month, his stocks have been fluctuating inversely each week. Stock A decreased by m cents per share and Stock B increased by n cents per share. Which equation can be used to find the total change in value of Jabari's shares?

Answers

This is how we solved and make the equation.
Stock A = 100
Stock B = 45

For the past months, his stocks inversely decreased.
Stock A = m cents / share
Stock B = n cents * share

So the equation is
= 100 (0.01m) + 45 (0.01n)
= m + 0.45n

What is 1/4 of $8.000 dollars?

Answers

$8000*(1)/(4)=(8000)/(4)=\$2000$

Suppose 5% of the population have a certain disease. A laboratory blood test gives a positive reading for 95% of people who have the disease. What is the probability of testing positive and having the disease?

Answers

Answer:

The probability of testing positive and having the disease is 4.75%.

Step-by-step explanation:

Solve each system by the addition method.-4x+7y =9
2y=-5x-22
Put the answer in (x,y) form

Answers

-4x + 7y = 9 ⇒ -4x + 7y = 9 ⇒    8x - 14y = -18
2y = -5x - 22 ⇒ -5x - 2y = 22 ⇒ -35x - 14y = 154
       43x = -172
      43    43
   x = -4
      -4x + 7y = 9
         -4(-4) + 7y = 9
      16 + 7y = 9
      - 16     - 16
      7y = -7
   7 7
      y = -1
      (x, y) = (-4, -1)

If there is an 80% chance of rain and a 50% chance of wind and rain, what is the probability that it is windy, given that it is rainy? Round your answer to the nearest percent.

Answers

Answer:

The probability that it is windy, given that it is rainy is:

62.5%≈63%

Step-by-step explanation:

Let A denote the event that it will rain.

B denote the event that it is windy.

A∩B denote the event that it is rainy and windy.

Let P denote the probability of an event.

i.e. we have:

P(A)=0.80

( Since there are 80% chance of rain)

P(A∩B)=0.50

(Since there are 50% chance of wind and rain)

We are asked to find:

P(B|A)

We know that:

$P(B|A)=(P(A\bigcap B))/(P(A))\n\n\nP(B|A)=(0.50)/(0.80)\n\n\nP(B|A)=0.625$

Hence, the probability in percent is:

62.5%≈63%

The total probability when given it is rainy is 80%. Among them, the windy probability among 80% is 50%. So the total probability is 50%/80%=62.5%≈63%.

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