For this case we have that by definition, the midpoint of a segment is given by:
We have the following ordered pairs:
Therefore, substituting values we have:
Rewriting we have:
Answer:
the coordinates of the midpoint of XY
y = 2x + 6
a. w-shaped; y-intercept (0,6); symmetrical with respect to the y-axis
b. o-shaped; y-intercept (0,6); symmetrical with respect to the y-axis
U-shaped; y-intercept (6, 0); assymmetrical with respect to the y-axis
n-shaped; y-intercept (0,6); assymmetrical with respect to the y-axi
Answer:
u-shaped; y-intercept (0,6); symmetrical with respect to the y-axis
Step-by-step explanation:
Given that y = 2x² + 6
The graph would be the shape of that of a parabola. It can be u shaped or n shaped depending on the value of the coefficient of a comparing with the standard equation y = ax² + bx + c. If a > 0, it is u shape and if a < 0, it is n shape.
For this question, since a > 0 it would be u shaped and the intercept can be gotten by putting x = 0.
Therefore y = 0² + 6 = 0
The intercept is at (0,6) and is symmetrical with respect to the y-axis
The domain of a function is the set of all possible input values (x). In terms of a real-world scenario where 'y' is a total cost or value, the domain refers to the quantities of a product or service (x) that would result in a total cost of $85.
The domain of a function in mathematics is the set of all possible input values (often designated by 'x'). But in the context of your question where y is a function and the total value is $85, it sounds like you could be referring to a real-world scenario where 'y' might represent a total cost or value in dollars. A function in this context might reflect how different quantities or 'x' values result in a certain cost or 'y' value.
For instance, if you're selling a product for $17 each and you want to know how many you would sell to reach a total of $85, the domain would be all possible amounts of units you could sell (0, 1, 2, 3, etc.). In this case, 5 units would yield a 'y' value of $85, since 5*$17 equals $85. So, the domain would include the number 5, along with any other positive integers up to the point where 'y' total value (the range) doesn't exceed $85.
#SPJ11
Answer:
***********o o**************
<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->
x>4 or x<-4
Step-by-step explanation:
You are looking for numbers that give you a distance, x, greater than 4 from 0. That wouldn't be anything between -4 and 4 because these would all give you a distance less than 4 from 0. So the answer would be to shade everything greater than 4 while also shading everything less than -4.
Here is a number line <-----|-----|-----|-----|-----|-----|-----|-----|-->
-6 -4 -2 0 2 4 6 8
Let's think about this more which of these numbers on this number line would satisfy |x|>4?
Numbers inside the numbers -4 and 4.
Or the numbers on the outside.
Let's try the inside numbers:
-2,02
|-2|>4
2>4 is false which means -2 doesn't satisfy |x|>4
|0|>4
0>4 is false which means 0 doesn't satisfy |x|>4
|2|>4
2>4 is false which means 2 doesn't satisfy |x|>4
We could also try -4 and 4... but these will both give you a distance equal to 4 from 0. And we are looking for greater than.
|-4|>4
4>4 is false which mean -4 doesn't satisfy |x|>4
|4|>4
4>4 is false which means 4 doesn't satisfy |x|>4
Now let's try the numbers on the outside:
-6,6,8
|-6|>4
6>4 is true so -6 does satisfy |x|>4
|6|>4
6>4 is true so 6 does satisfy |x|>4
|8|>4
8>4 is true so 8 does satisfy |x|>4
So what I'm trying to do is convince you more that the only numbers that would satisfy |x|>4 are numbers outside the interval from -4 to 4.
So x>4 or x<-4.
On a number line the solution would look like this:
***********o o**************
<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->
We have holes at -4 and 4 to mean we do not include those numbers. We would have if the inequality read . The line underneath this inequality means to include or equals. We do not want to include; we did not have the equal sign. The only difference between the two solutions would be to fill the holes if you .
***********o o**************
<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->