According to the concept of Avogadro's number there are 6.023×10²³ elementary entities in an element which when multiplied by atomic mass gives the mass of 1 mole of an element.
Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number.
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b. 29.9 L
c. 44.8L
d. 22.4 L
Answer: d. 22.4 L
Explanation:
According to Avogadro's law , 1 mole of every gas occupies 22.4 L of volume at STP.
moles of ammonia=
Given: Hydrogen is the excess reagent and nitrogen is the limiting reagent as it limits the formation of product.
From the given balanced equation:
2 moles of ammonia is produced by 1 mole of nitrogen.
Thus 2 moles of ammonia is produced by 22.4 L of nitrogen at STP as 1 mole of nitrogen occupies 22.4 L at STP.
Answer: grams
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles. and weighs equal to the molecular mass.
To calculate the moles, we use the equation:
1 mole of Americium weighs = 243 g
Thus of Americium weigh=
Thus the mass mass in grams of a sample of Americium containing six atoms is
The mass (in grams) of the sample of Americium containing six atoms is 2.42×10⁻²¹ grams
First, we shall obtain the mole of americium that contains six atoms. This is illustrated below:
From Avogadro's hypothesis,
6.022×10²³ atoms = 1 mole of americium
Therefore, we can say that
6 atoms = 6 / 6.022×10²³
= 9.96×10⁻²⁴ mole of americium
Finally, we shall determine the mass (in grams) of the americium. Details below:
Mass of americium = Mole × molar mass
= 9.96×10⁻²⁴ × 243
= 2.42×10⁻²¹ grams
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