Inscribed angles on the same intersecting arc are all equal.
Therefore we have the equation:
Answer:
in the explanation
Step-by-step explanation:
In the number line, the left most number would be -200 as it's the lowest, the middle would be -150, as this number is in between the other two, and the right most would be 75, as it's the greatest.
Hope this helps!
Answer: He will not have enough room
Step-by-step explanation: To determine if Andrew has enough room for his 250 CDs on the two shelves inside the bookcase, we need to calculate how many CD racks can fit on each shelf and how many CDs each of these racks can hold.
The bookcase is 3 ft wide, which is equivalent to 36 inches. Each shelf is 15 inches high. Therefore, the available space for CD racks on each shelf is 36 inches in width and 15 inches in height.
Each CD rack is 17 inches wide and 7 inches high. To calculate how many racks can fit on each shelf, we can use the following formula:
Number of racks on a shelf = (Width of shelf) / (Width of CD rack)
Number of racks on a shelf = 36 inches / 17 inches ≈ 2.12 (round down to 2, as you can't have a fraction of a rack)
Now, let's calculate how many CDs each of these racks can hold. Each CD rack can hold three stacks of 12 CDs each, for a total of 3 x 12 = 36 CDs.
So, on each shelf, Andrew can fit 2 CD racks, and each rack can hold 36 CDs. Therefore, each shelf can store 2 x 36 = 72 CDs.
Since Andrew has two shelves, he can store a total of 2 x 72 = 144 CDs in the bookcase.
So, he will be able to store 144 CDs in the bookcase, which is less than his 250 CDs. Therefore, he won't have enough room for all his 250 CDs in the bookcase, and he will need additional storage for the remaining CDs.
Answer:
I believe the median is 6.5
Step-by-step explanation:
Answer:
what is the question exactly??
can you please elaborate...
Step-by-step explanation: