A river flows at the rate of 30 feet per minute what is the rate in seconds per foot

Answers

Answer 1

Answer: 30 ft/ minute=30 ft/ minute*(1 minute / 60 s)=0.5 ft/s
rate in seconds per foot=1 / (0.5 ft/s)=2 s/ ft.

Answer:2 s/ft.

Related Questions

30 is 2 times as much as 15 true or false?
BEST ANSWER GETS BRAINLIESTT!! PLEASE HELPWhat conclusion can be determined from the dot plot below? A dot plot showing five dots above 9, six dots above 10, three dots above 11, and one dot above 12.The number of observations is 10.The median of the data set is 10.The mean of the data set is 15.The range of the data set is 12.
the relationship between x and y is proportional. when x is 3 and y is 15. what is x when y is 60? what is the value of x.
Simplify the following expression:12a+9b2a-13a2b2+4ab2-16a
Perpendicular distance between the planes 2x-y+2z=1 and 4x-2y+4z=1 is.......,Select the correct option from the given options.(a) 1/3 (b) 3 (c) 1/6 (d) 6

The data set below has an outlier.2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14

Which value is changed the most by removing the outlier?

A: the range
B: the median
C: the lower quartile
D: the interquartile range

Answers

Data set: 2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14

range: 14 - 2 = 12
median: 12
lower quartile = 10
interquartile range = 4

Data set w/o outlier 2: 10, 10, 11, 11, 12, 12, 12, 13, 14, 14

range: 14 - 10 = 4
median: 12
lower quartile: 10.5
interquartile range = 3.5

The value that change the most by removing the outlier is A.) THE RANGE.

To answer the problem above, we must define what an outlier is. An outlier is a number in a set of data that is smaller or larger than the rest of the data. In this problem, the outlier is 2. To know which value changed the most we solve each with and without the outlier.
A. range: 12(with), 4(without)
B. median: 12 (with), 12 (without)
C. lower quartile: 10.5(with), 11(without)
D. interquartile range: 2(with), 2(without)

The answer is A. range.

What is the problem of this solving?!

Answers

This question can be solved primarily by L'Hospital Rule and the Product Rule.

$y= \lim_(x \to 0) (x^2cos(x)-sin^2(x))/(x^4)$

I) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([2xcos(x)-x^2sin(x)]-2sin(x)cos(x))/(4x^3)$

II) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)])/(12x^2) \n y= \lim_(x \to 0) (2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x))/(12x^2)$

III) Product Rule and L'Hospital Rule:

$]y= \alpha + \beta \n \n \alpha =\lim_(x \to 0) (-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)])/(24x) \n \beta = \lim_(x \to 0) (4sin(x)cos(x)+4sin(x)cos(x))/(24x) \n \n y = \lim_(x \to 0) (-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x))/(24x)$

IV) Product Rule and L'Hospital Rule:

$y = \phi + \varphi \n \n \phi = \lim_(x \to 0) (-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)])/(24x) \n \varphi = \lim_(x \to 0) ([2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)])/(24x)$

V) Using the Definition of Limit:

$y= (-6*1-4*1-2*1+8*1^2)/(24) \n y= (-4)/(24) \n \boxed {y= (-1)/(6) }$

What is the value of x in the equation 4(2x + 10) = 0?−5

−7

5

7

Answers

4(2x+10)=0
8x+40=0
8x=-40
x=-40/8
x=-5

Answer:

x = -5

Step-by-step explanation:

i checked it with photo math

hey sales person sells $2900 and merchandise and earns a commission of 522 what is the commission rate?

Answers

Answer: 18%

Step-by-step explanation: To find the commission rate, we can divide the commission earned by the total merchandise sold.

Given:

Total merchandise sold = $2900

Commission earned = $522

To calculate the commission rate:

Commission rate = (Commission earned / Total merchandise sold) * 100%

Substituting the given values into the formula:

Commission rate = (522 / 2900) * 100%

Calculating the commission rate:

Commission rate = 0.18 * 100% = 18%

Therefore, the commission rate for this salesperson is 18%.

The value of a dirt bike decreases by 20% each year. If you purchased this dirt bike today for $500, to the nearest dollar how much would the bike be worth 5 years later?

Answers

The value of the bike after a year becomes only 80% of the value a year ago. In this given, the initial amount $500 should be multiplied by 80% 5 times. The answer would be $163.84. Thus, after 5 years the dirt bike would only be $163.84.

Answer:

The price of bike after 5 year in nearest dollars is $ 164

Step-by-step explanation:

We have formula

$A=P(1-R)^t$

Where

A= Price of dirt bike after t years

P= Initial price of bike

R= rate of decrease

t= time in years

It is given that the price of dirt bike today is $ 500, and its price is decreasing by 20% each year. We need to find the price after 5 years

So we have

P = $500

R = 20 % = 0.2

t= 5 years

now we plug these values in the formula, so we have the price of dirt bike after 5 years is given by

$A = 500(1-0.2)^5$

$A= 500(0.8)^5\nA= 500(0.32768)\nA= 163.84$

Hence the price of bike after 5 year in nearest dollars is $ 164

The product of two consecutive integers is 110. find the integers?

Answers

Hello,

I shall not resoved an 2th degree for that:

10*11=110 (evident)

When 10 and 11 (or -10 and -11) are multiplied, they equal 110.

You can find the answer by solving the following equation:
x(x+1)=110
x^2+x-110=0
(x-10)(x+11)=0

Therefore 10*11 and -10*-11 can be the possible answers to your question.

Other Questions

Solve the equation x^2-4x-21=0

A local little league has a total of 65 players, of whom 80% are left-handed. How many left-handed players are there?

How do you " find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches ?"

How many solutions are there to the equation below? 12x+6=5x