Which of the following is NOT a stage of cellular respiration?a. fermentation
b. electron transport
c. glycolysis
d. Krebs cycle

Answers

Answer 1
Answer:

Fermentation is the stage where it is not part of the cellular respiration. The answer is letter A. fermentation does not require oxygen to do respiration, rather, these are the glycolysis, Kreb’s cycle and electron transport.

Answer 2
Answer:

Fermentation is NOT a stage of cellular respiration. Therefore option A is correct.

Fermentation is not a stage of cellular respiration. Cellular respiration is the process by which cells break down glucose and other organic molecules to produce energy in the form of ATP (adenosine triphosphate).

It occurs in three main stages: glycolysis, the Krebs cycle (also known as the citric acid cycle or the tricarboxylic acid cycle), and the electron transport chain.

Fermentation is an alternative metabolic pathway that occurs in the absence of oxygen (anaerobic conditions). It is a partial breakdown of glucose or other organic molecules that do not involve the complete oxidation of glucose to produce ATP.

Instead, it produces a small amount of ATP and end products such as lactic acid or ethanol.

Therefore option A is correct.

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Two cars collide at an intersection. Car A, with a mass of 1900 kg, is going from west to east, while car B, of mass 1500 kg, is going from north to south at 17.0 m\s. As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 60.0degrees south of east from the point of impact.Part A WAS: How fast were the enmeshed cars moving just after the collision? I got 8.66 for velocity in part a which was CORRECT but i can't figure out PART B??...Part B:How fast was car A going just before the collision

Answers

Part A: The enmeshed cars were moving at a velocity of approximately 8.66 m/s just after the collision.

Part B: Car A was traveling at a velocity of approximately 8.55 m/s just before the collision.

How to compute the above velocities

To find the speed of car A just before the collision in Part B, you can use the principle of conservation of momentum.

The total momentum of the system before the collision should equal the total momentum after the collision. You already know the total momentum after the collision from Part A, and now you want to find the velocity of car A just before the collision.

Let's denote:

- v_A as the initial velocity of car A before the collision.

- v_B as the initial velocity of car B before the collision.

In Part A, you found that the enmeshed cars were moving at a velocity of 8.66 m/s at an angle of 60 degrees south of east. You can split this velocity into its eastward and southward components. The eastward component of this velocity is:

v_east = 8.66 m/s * cos(60 degrees)

Now, you can use the conservation of momentum to set up an equation:

Total initial momentum = Total final momentum

(mass_A * v_A) + (mass_B * v_B) = (mass_A + mass_B) * 8.66 m/s (the final velocity you found in Part A)

Plug in the known values:

(1900 kg * v_A) + (1500 kg * v_B) = (1900 kg + 1500 kg) * 8.66 m/s

Now, you can solve for v_A:

(1900 kg * v_A) + (1500 kg * v_B) = 3400 kg * 8.66 m/s

1900 kg * v_A = 3400 kg * 8.66 m/s - 1500 kg * v_B

v_A = (3400 kg * 8.66 m/s - 1500 kg * v_B) / 1900 kg

Now, plug in the values from Part A to find v_A:

v_A = (3400 kg * 8.66 m/s - 1500 kg * 8.66 m/s) / 1900 kg

v_A = (29244 kg*m/s - 12990 kg*m/s) / 1900 kg

v_A = 16254 kg*m/s / 1900 kg

v_A ≈ 8.55 m/s

So, car A was going at approximately 8.55 m/s just before the collision in Part B.

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Regan has an empty glass cup. it has a mass of 0.3 kg. she drops the cup on the ground and it shatters into several pieces. if she collected all of the pieces of the cup, how much mass would all of the pieces have combined?

Answers

0.3, because its the same thing, just in pieces. 

Suppose two waves collide and the temporary combined wave that results is smaller than the original waves. What term best describes this interaction?a. diffraction
b. destructive interference
c. standing wave formation
d. constructive interference

Answers

Answer: The correct answer is destructive interference.

Explanation:

Interference is the phenomenon in which there is a superposition of the waves. If the amplitude of the resultant wave is more than the original wave then there will be constructive interference.

If the amplitude of the resultant wave is lower than the original wave then there will be destructive interference.

Suppose two waves collide and the temporary combined wave that results is smaller than the original waves.

Therefore, the correct option is b.

the correct answer is B

Contrast generators and electric motors.

Answers

Answer:

A generator produces electricity when a conducting wire is rotated between magnetic field. Mechanical energy is converted to electrical energy. Fleming's right hand rule is used.

An electric motor does mechanical work using electrical energy. A current carrying coil is placed in magnetic field. A torque is exerted on the coil and it rotates. Electrical energy is converted to mechanical energy. Fleming's left hand rule is used.

generators take mechanical and output energy. electric motors take the input of electricity. 

Energy of a wave is measured in terms of the wave's ?

Answers

Answer: amplitude

Explanation: amplitude is a important measurement, it tells us how much energy a wave is carrying

Energy refers to the speed.So u use the formula speed=wavelength×frequency

When the engineer first sees the car, the locomotive is 100m from the crossing and its speed is 30m/s. If the engineer reaction time is 0.47 s what should the magnitude of the minimum deceleration to avoid an accident?

Answers

Answer:

The deceleration must have the engineer to avoid the accident is

a=-5.238 (m)/(s^(2) )

Explanation:

x_(0)=100m\nv_(0)=30 (m)/(s) \nt=0.47 s

While the engineer reacts the train continue moving so

x_(f) = v*t= 30(m)/(s) *0.47s= 14.1 m

x_(t)=  x_(o)+x_(f)\nx_(t)=  100m-14.1m=85.9m

Now the final velocity have to be zero so using equation can find deceleration

V_(f) ^(2) =V_(o) ^(2)+2*a*x_(f)\n  0= V_(o) ^(2)+2*a*x_(f)\na=-(V_(o) )/(2*x_(f))\na=-((30(m)/(s)) ^(2) )/(2*85.9m) \na=-5.238 (m )/(s^(2) ) } \n