Initially, we have 96 seats in the theater. However, due to 12 broken seats in the first 3 rows, 84 seats are usable.
To answer this question, we will use simple multiplication and subtraction techniques of Mathematics. This is about calculating the number of workable seats in a theater.
First, we need to calculate the total number of seats in the theater. There are 8 rows with 12 seats in each row. We multiply the number of rows by the number of seats in each row: 8 rows * 12 seats/row = 96 seats.
In the first 3 rows, there are 4 broken seats in each of these rows. We need to subtract these from the total number of seats: 3 rows * 4 broken seats/row = 12 broken seats.
Finally, we subtract the number of broken seats from the total number of seats to find out how many seats can be used: 96 seats - 12 broken seats = 84 usable seats.
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Answer:
H = 3 r - 5 .
Step-by-step explanation:
Given : The height ,H of a cylinder is 5 units less than 3 times the radius, r.
To find : What is an expression that can represent .
Solution : we have given that
The height ,H of a cylinder is 5 units less than
3 times of radius = 3 *r
H = 3 r - 5 ( negative sign for less than )
Therefore, H = 3 r - 5 .
Answer:
The distance written as a decimal is 3.7
To write 3 7/10 miles as a decimal, multiply the whole number by the denominator and add the numerator, then write the result over the denominator. Simplify the fraction if possible.
To write the distance in decimal form, we need to convert the mixed number to a decimal. The given distance is 3 7/10 miles. To do this, we multiply the whole number, 3, by the denominator, 10, and add the numerator, 7. So, 3 multiplied by 10 plus 7 equals 37. Then, we write 37 over the denominator 10, giving us 37/10. Finally, we can simplify this fraction by dividing the numerator and denominator by their greatest common factor, which in this case is 1. Dividing 37 by 1 gives us 37, and dividing 10 by 1 gives us 10. Therefore, the distance of 3 7/10 miles can be written as the decimal 3.7 miles.
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is there a picture we can use to understand this?
Answer:
Answers will vary. For example, plugging in the test point (0, 0):
x + y ≤ 900
0 + 0 ≤ 900
0 ≤ 900
The test point (0, 0) holds true for the inequality.