2/3 (y+57 )= 178
The value of the mathematical expression 6n(n−1)+4 when n=3 is 40. This involves plugging in the value of n=3 into the expression and simplifying it according to the order of operations.
This is a simple math algebra problem about plugging in values and solving expressions. The given equation is 6n(n−1)+4, and we are asked to find the value when n=3. Let's start by replacing n with 3 in the equation.
So, 6n(n-1)+4 becomes 6*3*(3-1)+4. Simplifying inside the parenthesis first (according to the order of operations), we get 6*3*2+4, which becomes 18*2+4, then 36+4. Finally, that simplifies to 40.
So, the value of 6n(n-1)+4, when n=3 is 40.
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Answer:
48%
Step-by-step explanation: