PLZ HELP ME GEOMETRY
question is below

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Answer 1

Answer:

The missing justification is for the statement that three angles add to a particular angle. The appropriate choice is ...

... c. Angle Addition Postulate

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X-y/2z=3
Solve for x will mark brainliest

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The answer is x = 6z+y

PLEASE HELP, TY! WILL MARK BRAINLIEST!

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Answer: y = 6

Step-by-step explanation:

The opposite sites of a parallelogram should be equal length. Therefore $7y = y + 36$ , so $6y = 36$ and thus $y = \boxed{6}$ .

How do you do this question?

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Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

The temperature in Fargo was -6 degrees C at 10 a.m. by noon the temperature went up 4 degrees

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Answer:

The answer is B) point b hope this helps

Step-by-step explanation:

Point B or the second responce the point is that you chose answer B hope it helps and if it helps bote or click thanks it was a honor to help you

Given f '(x) = (2 - x)(6 - x), determine the intervals on which f(x) is increasing or decreasing. (2 points)Decreasing (-∞, 2); increasing on (6, ∞)
Decreasing (2, 6); increasing on (-∞, 2) U (6, ∞)
Decreasing (-∞, 2) U (6, ∞); increasing on (2, 6)
Increasing (-∞, -2) U (-6, ∞); increasing on (-2, -6)

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Answer:

Decreasing (2, 6); increasing on (-∞, 2) U (6, ∞)

Step-by-step explanation:

To determine where $f(x)$ is increasing or decreasing, we set $f'(x)=0$ and check for the intervals.

We see that $f'(x)=0$ when either $x=2$ or $x=6$ . Therefore, we'll need to check the intervals $(-\infty,2)$ , $(2,6)$ , and $(6,\infty)$

For the interval $(\infty,2)$ , we can pick $x=0$ . This means that $f'(0)=(2-0)(6-0)=(2)(6)=12>0$ , showing that $f(x)$ increases on the interval $(-\infty,2)$

For the interval $(2,6)$ , we can pick $x=4$ . This means that $f'(4)=(2-4)(6-4)=(-2)(2)=-4<0$ , showing that $f(x)$ decreases on the interval $(2,6)$

For the interval $(6,\infty)$ , we can pick $x=7$ . This means that $f'(7)=(2-7)(6-7)=(-5)(-1)=5>0$ , showing that $f(x)$ increases on the interval $(6,\infty)$