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Which inequalities are equivalent to r + 45 < 16? Check all that apply.r + 45 < 16 - 45
r + 45 – 16 < 16 – 16
r + 45 + 3 < 16 + 3
r + 45 - 16 < 16
r + 45 - 45 < 16 - 45

Answers

Answer 1

Answer:

Answer

Which inequalities are equivalent to r + 45 < 16? Check all that apply.

✅r + 45 – 16 < 16 – 16

✅ r + 45 + 3 < 16 + 3

✅r + 45 - 45 < 16 - 45

Answer 2

Answer: the last option I'm thinking, hope this helps

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How to convert from point slope form to slope intercept form

Answers

Answer:

$y=mx+(y_1-mx_1), b=y_1-mx_1$

Step-by-step explanation:

The point slope form of the equation of a line is given as:

$y-y_1=m(x-x_1)$

The slope-intercept form of the equation of a line is given as:

$y=mx+b$

where: m=slope, b=y-intercept.

To convert from the point slope form to slope intercept form, follow these steps:

Step 1: Distribute the right hand side

$y-y_1=m(x-x_1)\ny-y_1=mx-mx_1$

Step 2: Isolate the y variable

$y=mx-mx_1+y_1\ny=mx+(y_1-mx_1)$

This is the slope-intercept form. We can evaluate $y_1-mx_1 $ given values for $(x_1,y_1)$ and slope, m$

Which of the following rules best describes the matrix belowa. dilation of scale factor 2
b. reflection over the y-axis
c. reflection over the line y = x
d. translation 1 unit left and 1 unit up

Answers

Answer: D

Step-by-step explanation:

d. translation 1 unit left & 1 unit up

right on edg

Need Help on this, First RIGHT answer gets brainliest :)

Answers

Answer:

50%

Step-by-step explanation:

The circle is split into 4 parts and there are 2 parts of the circle shaded.

Step 1:

2/4 = 50/100

Step 2:

50/100 = 50%

Answer:

50%

Hope This Helps :)

the answer is 50% as half the circle is shaded!

What is x in this problem? someone please help

Answers

X=21
This is because both of those angles are equal, so you would divide 42 by 2 and get 21

The number of text messages sent by 25 13-year-olds over the past month are as follows791 542 671 672 555 582 616 961 639
691 648 967 959 826 573 598 790 954
711 515 649 960 949 802 507
a. Construct the frequency distribution using classes of 500 up to 600, 600 up to 700, etc.
Texts Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
Total
b. Construct the relative frequency distribution, the cumulative frequency distribution and the cumulative relative frequency distribution. (Round "Relative Frequency" and "Cumulative Relative Frequency" to 2 decimal places.)
Texts Relative Frequency Cumulative Frequency Cumulative Relative Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
c-1. How many of the 13-year-olds sent at least 600 but less than 700 text messages?
c-1. Number of 13-year-olds
Number of 13-year-olds
c-2. How many sent less than 900 text messages?
Number of 13-year-olds
d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %
d-5. What percent of the 13-year-olds sent less than 600 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %

Answers

Answer:

7 ; 19 ; 8% ; 28%

Step-by-step explanation:

Given the data:

791 542 671 672 555 582 616 961 639

691 648 967 959 826 573 598 790 954

711 515 649 960 949 802 507

How many of the 13-year-olds sent at least 600 but less than 700 text messages? = 7

c-2. How many sent less than 900 text messages? = (7 + 7 + 3 + 2) = 19

d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? =0.08 × 100 = 8% (from relative frequency)

d-5. What percent of the 13-year-olds sent less than 600 text messages? 0.28 × 100 = 28% (from relative frequency)

Final answer:

By sorting text messages into classes, we can get the frequency distribution. From there, we can determine the relative and cumulative frequencies. Finally, we can examine how many students sent texts within certain ranges and express these as percentages.

Explanation:

To answer this question, let's first classify the amount of text messages sent by each of the 25 13-year-olds into groups or classes of 100. Then we count the frequencies, or how many text messages fall into each class. This helps us construct the frequency distribution.

The classes are: 500-600, 600-700, 700-800, 800-900, and 900-1000.

Next, we calculate the relative frequency by dividing the frequency of each class by the total number of students. We round each relative frequency to 2 decimal places.

To calculate cumulative frequency, we keep an ongoing total of frequencies as we move up the classes. The cumulative relative frequency is computed similarly but applied to the relative frequencies.

In the last part, we determine how many 13-year-olds sent at least a certain number of texts but less than another number, and convert these to percentages.