Answer:
Step-by-step explanation:
11)
Subtract 4 from both sides. Square each side. Subtract 33 from both sides. Divide each side by 8. Your answer is -3.
12)
Square both sides. Put all numbers on one side of the equation so that you can be equal to zero. Factor out and solve for x.
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Use 3.14 to approximate pi and express your answer in hundredths.
cm3
The requried Zuri used 56901.16 cubic cm more plaster for the larger sphere than for the smaller sphere.
Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.
The formula for the volume of a sphere is V = (4/3)πr³, where r is the radius.
For the smaller sphere, the volume is:
V1 = (4/3) x 3.14 x 6³
V1 = 904.32 cubic cm
For the larger sphere, the volume is:
V2 = (4/3) x 3.14 x 24³
V2 = 57905.76 cubic cm
To find out how much more plaster Zuri used for the larger sphere, we need to subtract the volume of the smaller sphere from the volume of the larger sphere:
V2 - V1 = 57905.76 - 904.32
V2 - V1 = 56972.16 cubic cm
Therefore, Zuri used 56901.16 cubic cm more plaster for the larger sphere than for the smaller sphere.
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B y=70x+100 D y=70x
Speed is the rate of change of distance over time.
The equation that shows the relationship is
The given parameters are:
Distance = 100 yards
Speed = 70 miles per hour
Speed is calculated as:
So, we have:
Multiply both sides by x
Hence, the equation that shows the relationship is
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Answer with Step-by-step explanation:
The cheetah was clocked running 70 miles per hour.
i.e. in 1 hour cheetah covered 70 miles
in 2 hours cheetah covered 140 miles
in 3 hours cheetah covered 210 miles
in general, in n hour cheetah covered 70n miles
If y denote the distance covered
and x denotes the time cheetah runs
Then, y=70x
Hence, the equation which shows the relationship between the distance, y, and time, x, the cheetah runs is:
D y=70x
Tony sail 2.6 width of the reservoir.
To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
A reservoir is 3 1/4 miles wide.
And, Tony sailed 4/5 the width of the reservoir.
Hence, The sail width of the reservoir is,
⇒ 4/5 of 3 1/4
⇒ 4/5 × 13/4
⇒ 13/5
⇒ 2.6
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