years or 0.1 million years
B) x^2 + 9x – 2
C) 16x^2 + 4x – 6
D) 4x^2 + 20x – 2
The value for the compositefunction is 4x² + 20x - 2.
Option D is the correct answer.
A function has an input and an output.
A function can be one-to-one or onto one.
It simply indicated the relationships between the input and the output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
We have,
To find (C o D)(x), we need to substitute d(x) into c(x) and simplify the resulting expression.
First, we have:
C(D(x)) = 4D(x) - 2
Next, we substitute d(x) for x in the expression for D(x):
D(x) = x² + 5x
So,
C(D(x)) = 4(x² + 5x) - 2
Simplifying, we get:
C(D(x)) = 4x² + 20x - 2
Therefore,
The value for the compositefunction is 4x² + 20x - 2.
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Answer:
try 70
Step-by-step explanation:
What is the radius of the circle?
2
,−7)V, left parenthesis, square root of, 2, end square root, comma, minus, 7, right parenthesis lie?
Answer:
inside the circle
Step-by-step explanation:
Khan Academy
The point V(√2, -7) lies inside the circle centered at K(0,0) with point U(6, -4) on it. This is determined by comparing the distances (or radii) from the circle center to the points.
To determine where the point V(√2, -7) lies in relation to the circle centered at K(0,0) with point U(6, -4) on the circle, we first need to identify the radius of the circle. The radius can be found using the distance formula for points in the Cartesian plane,
Distance = √[(x2-x1)^2 + (y2-y1)^2]
So the distance between points K(0,0) and U(6, -4) (which is the radius of our circle) is √[(6-0)^2 + (-4 - 0)^2] = √[36 + 16] = √52
Now we calculate the distance between the circle center K(0,0) and point V(√2, -7) using the same formula. This results in a distance of √[(√2 - 0)^2 + (-7 - 0)^2] = √[2 + 49] = √51.
Since √51 is less than √52, the point V(√2, -7) lies inside the circle.
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Answer:
answer Z
Step-by-step explanation:
Look for a graph that contains the following zeros: x = 1, x = 2 , x= 3, following the info derived by the binomial factors that the function contains. Also look ate the fact that the function in question has for leading term positive , then this function must go towards plus infinity when x becomes large. This is the case for the graph option Z (the last graph of the group)