Please help with this Pythagoras' theorem
Thank you

Answers

Answer 1

Answer: Omg that's easy, a^2 + b^2=c^2. The longest side is your hypotenuse. The shortest side is your A. Basically just plugging it in. After you set it up you unsquare it. Then find the square root of the missing side. This is from my knowledge, so if you're still confused, ask your teacher for clarification, because it took me the second day to get it. Or just watch a video on it.

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Factoring trinomials word problems.

Answers

So see if u can factor out the trinomial.
it's factorable.
(x+3)(×-2)

so divide that factors by (×-2)

(×-2)(×+3)
---------
(×-2)

the (×-2) cancel out, leaving x+3

If a bottle of medication must be stored at a temperature cooler than 45 degrees f, what is the Celsius temperature at which the medication must be stored

Answers

We must first convert this degrees Farenheit to degrees Celscius by using the available formula according to its conversion. Farenheit to Celscius is solved by the formula using: (°F - 32) multiplied by 5/9 =°C. Then, substitute the values in the formula from the given of 45 degrees Farenheit which answer would be 7.2°C.

The diameter of a circle is 21 inches. Find the area of the circle. (Use 22/7 as the approximation of pi.)

Answers

Step-by-step explanation:

Area of a circle is pi times r-square

$\pi \: {r}^(2)$

So...

$(22)/(7) * (21)/(2) * (21)/(2) = \frac{22 * {21}^(2) }{28}$

Do the rest yourself, my calculator and pen are not handy.Sorry

What are the answers and why?

Answers

Answer:

$\boxed{\text{(v) and (viii)}}$

Step-by-step explanation:

The three step test for continuity states that a function ƒ(x) is continuous at a point x = a if three conditions are satisfied:

f(a) is defined.
The limit of ƒ(x) as x approaches a exists.
The limit of ƒ(x) as x approaches a is equal to f(a).

(i) Left-hand limit = right-hand limit.

Pass. The limit from either side is 8.

(ii) Left-hand limit = limit.

Pass. If the limits from either direction exist, the limit exists.

(iii) Limit as x ⟶ ∞ is not part of the three-step test.

(iv) Limit as x ⟶ 1 exists. Pass.

(v) f(1) is defined.

FAIL. f(1) is not defined.

(vi) Limit as x ⟶ ∞ is not part of the three-step test.

(vii) Passing the three-step test is not a step in the test.

(viii) The limit as x ⟶ 1 does not equal f(1).

FAIL. f(1) is undefined.

The steps in the three-step test for which the function fails are $\boxed{\textbf{(v) and (viii)}}$ .

Solve for x.

−10<−2x+4≤8

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$-10 < -2x+4\leq8\ \ \ \ |-4\n\n-14 < -2x\leq4\ \ \ \ |\text{change the signs}\n\n14 > 2x\geq-4\ \ \ \ |:2\n\n\boxed{7 > x\geq-2}\to\boxed{-2\leq x < 7}$