Two tomato seeds were planted and watered after six weeks ,plant was 26cetmeters tall.the plant only 74% as tall what was hight the plant

Answers

Answer 1

Answer: The shorter plant was 19.24 cm in height.
74% is equal to 0.74, so the height of the shorter plant can be found by multiplying 0.74 by the height of the taller plant, 26 cm.

26 * 0.74 =19.24
so the height of the shorter plant is 19.24 centimeters

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Given a=5, d=3,an =50 .find the n and 5n

Answers

Answer:

Step-by-step explanation:

an = 50

a +(n-1)d = 50

5 + (n-1)*3 = 50

(n-1)*3 = 50 - 5 = 45

n-1 = 45/3

n-1 = 15

n=15+1 = 16

n = 16

Answer:n=10, 5n=50

Step-by-step explanation:

an=50

n=50/a

n=50/5=10

5n=5×10=50

What are the intercepts on a graph for y=4x-2

Answers

The intercepts for this equation is (1/2,-2) I hope this helps

the x intercept is where the line crosses the x axis or where y=0
the y intercept is where the line crosses the y axis or where x=0

x intercept
solve for where y=0

0=4x-2
add 2
2=4x
divide 4
1/2=x
x intercept at x=1/2 or at the point (1/2,0)

y intercept
x=0
y=4(0)-2
y=0-2
y=-2
y intercept at y=-2 or the point (0,-2)

x intercept at x=1/2 or at the point (1/2,0)
y intercept at y=-2 or the point (0,-2)

URGENT!Kate has an equal number of coins in three bags.

( 20p coins ) (50p coins ) ( 5p Coins )

She exchanges them at the bank for 2 notes.

Circle the number of coins in each bag.

⇒ 10?
⇒ 15?
⇒20?
⇒ 25?
⇒ 40?

Answers

25 coins because 50+20+5 = 75. Then divide 75 by 3 = 25. Each bag has 25 coins.

Hope that helps!!

She has

20 coins
50 coins
5 coins

How many coins in total?

20 + 50 + 5
70 + 5
75

Find in each bag;-

3 bags
75 ÷ 3 = 25
25 coins per bag

Check:-
25 × 3 = 75
Correct!

D) 25 coins per bag.

rhe math club is selling pencil cases to raise money for a field trip rhe field trip costs $508 of wich they already have $76 how many p pencil cases for $2 each do they need to sell or raise enough money?

Answers

how much do they need

508-76 = 432

they need 432

each pencil case costs 2 dollars

divide 432 by 2 dollars to determine the number of pencil cases needed

432/2 =216

they need 216 pencil cases

as an equation

508 =76+2p

Answer: 216 pencil cases

Allison is running a race that is m miles long. She has already run 6 miles. Which expression shows how many miles Allison has left to run?

Answers

m-6 is the expression that shows how far Allison has to run

An expression that can be used to show how many miles Allison has left to run would be 6-m. Hope this helped :D

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=5.Calculate (a)the common ratio. (b)the first term of this geometric sequence

Answers

1 step: $S_(5)=T_(1)+T_(2)+T_(3)+T_(4)+T_(5)$ , $S_(3)=T_(1)+T_(2)+T_(3)$ , then
$S_(5)-S_(3)=T_(4)+T_(5)=5$ .

2 step: $T_(n)=T_(1)*q^(n-1)$ , then
$T_(6)=T_(1)*q^(5)$
$T_(5)=T_(1)*q^(4)$
$T_(4)=T_(1)*q^(3)$
$T_(3)=T_(1)*q^(2)$
and $\left \{ {{T_(6)-T_(4)= (5)/(2) } \atop {T_(5)+T_(4)=5}} \right.$ will have form $\left \{ {{T_1*q^(5)-T_(1)*q^(3)= (5)/(2) } \atop {T_(1)*q^(4)+T_(1)*q^(3)=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^(3)*(q^(2)-1)= (5)/(2) } \atop {T_(1)*q^(3)*(q+1)=5} \right.$ and dividing first equation on second we obtain $(q^(2)-1)/(q+1)= ( (5)/(2) )/(5)$ . So, $((q-1)(q+1))/(q+1) = (1)/(2)$ and $q-1= (1)/(2)$ , $q= (3)/(2)$ - the common ratio.

4 step: Insert $q= (3)/(2)$ into equation $T_(1)*q^(3)*(q+1)=5$ and obtain $T_(1)* (27)/(8)*( (3)/(2)+1 ) =5$ , from where $T_(1)= (16)/(27)$ .

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