10001, being an odd number, cannot be expressed as the sum of two prime numbers following the Goldbach's conjecture in mathematics. Hence, the answer is 0 ways.
The question asks in how many ways can 10001 be written as the sum of two primes. This question relates to the concept of Goldbach's conjecture in mathematics, which states that any even integer greater than 2 can be written as the sum of two primes. Since 10001 is an odd number and greater than 2, the conjecture doesn't apply, hence there isn't any way to represent 10001 as the sum of two prime numbers. So, the answer is option a. 0.
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The easiest way I have for knowing the difference between linear and nonlinear is the exponent value on the variable x. It is important to understand the root word in linear. It is LINE. A straight line, no curves .y = 2x - 3 This is linear because the exponent on x is one. Thus your slope is standard rise over run, like a stair step and simply goes up or down. I hope this helps :D
Given the conversion rate of 1 gallon = 16 cups and that 1/2 cup of milk makes 12 muffins, you can make 32 batches of 12 muffins using one gallon of milk.
The subject we are dealing with here is Mathematics and it's about a practical application of ratios and conversions. The student wants to know how many batches of 12 muffins can be made using one gallon of milk, given that 1/2 cup of milk makes 12 muffins.
To solve this, we first need to understand the relationship between gallons and cups. Specifically, 1 gallon is equivalent to 16 cups. If 1/2 cup of milk makes 12 muffins, hence 1 gallon, or 16 cups, will make 2 batches/cup x 16 cups/gallon = 32 batches of muffins.
Therefore, one gallon of milk can be used to bake 32 batches of 12 muffins each.
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The fraction of the amount Liang has left is
To derive L (amount of money Liang will have left), add X (amount spent on a pen) and Y (amount spent on books) together, then the derived value be subtracted from M (fraction of total amount Liang has got) i.e.: M – (X + Y)
Therefore, L = M – (X + Y)
Deriving (X + Y)
= X + Y
= +
= (1 x 7) + (3 x 4) / 21
= (7) + (12) / 21
= 7 + 12 / 21
=
X + Y =
Since the lowest common denominator of the fraction of X and Y = 21, then the fraction of M =
Thus, M =
Recall, L = M – (X + Y)
Thus,
L = –
L = (1 x 21) – (1 x 19) / 21
L = (21) – (19) /21
L = 21 – 19 /21
L =
Hence, the amount Liang will have left is
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13(19 – x)