Answer:
JK = 83 , m∠A = 70° , m∠ALM = 110°
Step-by-step explanation:
* Lets explain how to solve the problem
∵ ABCD is a trapezoid
∴ DC // AB
∴ m∠D + m∠A = 180° ⇒ interior supplementary angles
∵ m∠D = 110°
∴ 110° + m∠A = 180° ⇒ subtract 110° from both sides
∴ m∠A = 70°
∵ L is the midpoint of AD, and M is the midpoint of BC
∴ LM is the median of trapezoid ABCD
∴ LM // AB and DC
∴ m∠D = m∠ALM ⇒ corresponding angles
∵ m∠D = 110°
∴ m∠ ALM = 110°
- The length of the median is half the sum of the lengths of the two
parallel bases
∴ LM = 1/2 (AB + DC)
∵ AB = 96 units and DC = 44 units
∴ LM = 1/2 (96 + 44) = 1/2 (140) = 70 units
- In the quadrilateral ABML
∵ AB // LM
∵ AL ≠ BM
∴ ABML is a trapezoid
∵ JK is its median
∴ JK = 1/2 (AB + LM)
∵ AB = 96 units ⇒ given
∵ LM = 70 units ⇒ proved
∴ JK = 1/2 (96 + 70) = 1/2 (166) = 83
∴ JK = 83 units
100 beans and marks them.
Then she returns them to the jar and mixes them with the unmarked beans. She then gathers some data by taking a sample of beans from the jar. Use her data to predict the number of beans in the jar.
Answer:
62
Step-by-step explanation:
1. 16/ 2
2. 4*8=32
3. 32+32=64
4. 64-2=62
Y= 16x + 2.50
y<=-2x-3
y>=3x+2
1. If we multiply by three the numerator of a fraction and add 12 to the denominator, the value of the fraction is three quarters, and if the numerator increases in 7 and the denominator trebles the value of the fraction is a way, finds the fraction.
Please I am grateful for them to him very much thank you for the given attention...:)
Answer:
The bottom right, middle top, and bottom left are NOT cubes.
Step-by-step explanation:
Cubes are defined as a three dimensional object with the same length, width, and height. Since the square on the bottom left is two dimensional, It is not a cube. Since the hexagon on the bottom right is two dimensional, It can't be a cube. The Middle top shape doesn't have the same length height as it's width is, so it is not a cube. The rest are cubes.
Answer: Circle 1st, 2nd, 4th, and 6th
Step-by-step explanation:
A cube is 4 perfect squares in a 3-D shape. Only shape 3 and 5 show this.