3x^2-7x+4=0 solve for x. Write both solutions separated by a comma

Answers

Answer 1
Answer: Hi \n \n 3x\²-7x+4 ~~--\ \textgreater \ \boxed{(-b\pm √(b\²-2ac) )/(2a) } \n a=3 \n b=-7 \n c=4 \n \n x= (7\pm √((-7)\²-2.3.4 ) )/(2.(3)) \n \n x= (7\pm5)/(6) \begin{cases}x_1= (7+5)/(6)=2 \n \n x_2= (7-5)/(6)= (1)/(3) \end{cases} \n \n \therefore~(2; (1)/(3)) \n \n \n
Answer 2
Answer: 3x²-7x+4=0
3x²-3x-4x+4=0
3x(x-1)-4(x-1)
(x-1)(3x-4)
x=1 x=4/3

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A rotating light on top of a lighthouse sends outrays of light in opposite directions. As the beacon
rotates, the ray at an angle 8 makes a spot of light
that moves along the shore. The lighthouse is
located 500 m from the shoreline and makes
one complete rotation every 2 min.
Determine the equation that expresses the
distance, d, in metres, as a function
of time, t, in minutes.

Answers

Answer:

\sf d = 500 \cdot (\theta(t))

Step-by-step explanation:

The equation can be derived using the following trigonometric identity:

That is:

\sf tan(\theta) =( opposite )/( adjacent)

In this case, the opposite side is the distance from the lighthouse to the shoreline and the adjacent side is the distance from the lighthouse to the spot of light on the shoreline (500m)

The angle is equal to the angle of the light beam.

It is changeable according to the time. so,

\sf \theta \textsf{ will be } \theta t

Substituting these values into the trigonometric identity gives us the following equation:

\sf tan(\theta t) = (d)/(500)

Solving for d gives us the following equation:

\sf d = 500 \cdot (\theta(t))

Therefore, the equation to express the distance, d, in metres, as a function of time, t, in minutes is:

\sf d = 500 \cdot (\theta(t))

What is the value of the expression below when c - 5 and d - 4 (c is to the second power)?6c2-5d+8

Answers

Well, let's write it out, shall we? 6c2-5d+8 Now plug in the numbers. 6(5^2)2-5(4)+8 Now simplify using PEMDAS Parentheses Exponents Multiplication Division Addition and Subtraction (They go together go from left to right in the equation) 5^2= 5*5 = 25 6 * 25 = 150 150 * 2 = 300 5 * 4 = 20 Rewrite the equation. 150-20+8 Use PEMDAS again ( refer to the previous mentioning) 150 - 20 = 130 130 + 8 = 138

Ms. Scott wrote a test. Part A had true/false questions, each worth 6 points. Part B had multiple choice questions, each worth 4 points. She made the number ofpoints for Part A equal the number of points for Part B. It was the least number of points for which this was possible,
Answer the following questions.
How many points was each part worth?
points
How many questions did Part A have?
questions
How many questions did Part B have?
questions

Answers

Answer:

1. How many points was each part worth?

 - 12 points

2. How many questions did part A have?

 - 2 questions

3. How many questions did Part B have?

 - 3 questions

Step-by-step explanation:

We can set up our equation like this:

6x = 4y

In the above equation, x is representing the number of true/false questions and y is representing the nymber of multiple choice questions.

Now, the problem tells us that they want the least number of points possible so we know we need to use low numbers.

Since 6 is higher than 4, it's easier to go off of there.

6 x 1 = 6                        4 is too big to go into 6 so we will move on.

6 x 2 = 12                      4 goes into 12 3 times so we can use this.

Now that we've figured this out, we can put it in our equation:

6(2) = 4(3)

In the above equation, we can see that I've put 2 in for x because we multiplied 6 by 2 to get 12. I also put 3 in for y because we multiplied 4 by 3.

Now we can start with the questions:

1. How many points was each part worth?

Each part was worth 12 points because we can multiply 6 by 2 and get 12 or 4 by 3 and get the same thing

2. How many questions did part A have?

Part A had 2 questions because this is what x was when we multiplied by 6

3. How many questions did Part B have?

Part B had 3 questions because this is what y was when we multiplied by 4

Hope this helps!!

Final answer:

Each part is worth 12 points. Part A has 2 questions. Part B has 3 questions.

Explanation:

The problem states that the number of points for Part A is equal to the number of points for Part B, and we need to find the least number of points for which this is possible. Let's represent the number of questions in Part A as x. Since each true/false question is worth 6 points, the total points for Part A will be 6x. Similarly, let's represent the number of questions in Part B as y. Since each multiple choice question is worth 4 points, the total points for Part B will be 4y. To find the least number of points for which the two parts are equal, we need to find the smallest common multiple of 6 and 4.

The prime factorization of 6 is 2 x 3.

The prime factorization of 4 is 2 x 2.

From the prime factorization, we can see that the least common multiple (LCM) of 6 and 4 is 2 x 2 x 3 = 12.

Therefore, each part is worth 12 points.

To find the number of questions in Part A and Part B, we can substitute 12 for the total points in each part and solve for x and y:

6x = 12

x = 2

4y = 12

y = 3

Learn more about Least Common Multiple here:

brainly.com/question/34291727

#SPJ2

Find the 4th term in the binomial expansion(2x+3y)^6


2916xy^5

4320x^3y^3

4860x^2y^4

2160x^4y^2

Answers

if u do the math u woud get something like this:

...x^6 + ...x^5y + ...x^4y^2 + ... x^3 y^3 +... x^2 y ^4 + ... x y^5 + ... y^6 

so 4th term need to have x^3 y^3 
then its 4320x^3y^3

The greatest product of a 3 digit number and a 1 digit number is 8,891. is it correct?

Answers

no, 9 is the biggest single digit number and 999 is the biggest 3 digit number. 9x999 is 8991
the biggest 3 digit number is 999 since 9 is highest single digit number
highest singel digit numbe ris 9 so
9 times 999=8991
so you are incorrect unless you made a typo

Sam’s Music Store wanted to take a survey of the age range of people that visited the store. Over the course of a week, they asked 40 people their age as they walked in. Below is a box plot of the collected data. Answer the following questions about the box plot in relation to the problem. 1.When Sam’s assistant was collecting the data she mistakenly noted that the oldest person was 48. The oldest person was actually 50. How will this affect the box plot?

Answers

A box plot contains 5 number summary. The information gathered from the box plot are:
1) minimum number
2) 1st quartile
3) median
4) 3rd quartile
5) maximum

Since the box plot of the collected data is not shown, I can only say that the maximum number will be affected by the error.

maximum number of 48 should have been maximum number 50.