rotates, the ray at an angle 8 makes a spot of light
that moves along the shore. The lighthouse is
located 500 m from the shoreline and makes
one complete rotation every 2 min.
Determine the equation that expresses the
distance, d, in metres, as a function
of time, t, in minutes.
Answer:
Step-by-step explanation:
The equation can be derived using the following trigonometric identity:
That is:
In this case, the opposite side is the distance from the lighthouse to the shoreline and the adjacent side is the distance from the lighthouse to the spot of light on the shoreline (500m)
The angle is equal to the angle of the light beam.
It is changeable according to the time. so,
Substituting these values into the trigonometric identity gives us the following equation:
Solving for d gives us the following equation:
Therefore, the equation to express the distance, d, in metres, as a function of time, t, in minutes is:
Answer the following questions.
How many points was each part worth?
points
How many questions did Part A have?
questions
How many questions did Part B have?
questions
Answer:
1. How many points was each part worth?
- 12 points
2. How many questions did part A have?
- 2 questions
3. How many questions did Part B have?
- 3 questions
Step-by-step explanation:
We can set up our equation like this:
6x = 4y
In the above equation, x is representing the number of true/false questions and y is representing the nymber of multiple choice questions.
Now, the problem tells us that they want the least number of points possible so we know we need to use low numbers.
Since 6 is higher than 4, it's easier to go off of there.
6 x 1 = 6 4 is too big to go into 6 so we will move on.
6 x 2 = 12 4 goes into 12 3 times so we can use this.
Now that we've figured this out, we can put it in our equation:
6(2) = 4(3)
In the above equation, we can see that I've put 2 in for x because we multiplied 6 by 2 to get 12. I also put 3 in for y because we multiplied 4 by 3.
Now we can start with the questions:
1. How many points was each part worth?
Each part was worth 12 points because we can multiply 6 by 2 and get 12 or 4 by 3 and get the same thing
2. How many questions did part A have?
Part A had 2 questions because this is what x was when we multiplied by 6
3. How many questions did Part B have?
Part B had 3 questions because this is what y was when we multiplied by 4
Hope this helps!!
Each part is worth 12 points. Part A has 2 questions. Part B has 3 questions.
The problem states that the number of points for Part A is equal to the number of points for Part B, and we need to find the least number of points for which this is possible. Let's represent the number of questions in Part A as x. Since each true/false question is worth 6 points, the total points for Part A will be 6x. Similarly, let's represent the number of questions in Part B as y. Since each multiple choice question is worth 4 points, the total points for Part B will be 4y. To find the least number of points for which the two parts are equal, we need to find the smallest common multiple of 6 and 4.
The prime factorization of 6 is 2 x 3.
The prime factorization of 4 is 2 x 2.
From the prime factorization, we can see that the least common multiple (LCM) of 6 and 4 is 2 x 2 x 3 = 12.
Therefore, each part is worth 12 points.
To find the number of questions in Part A and Part B, we can substitute 12 for the total points in each part and solve for x and y:
6x = 12
x = 2
4y = 12
y = 3
#SPJ2
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