The answer to the question is 25.
slope:
What does the numerical value of the slope tell you?
The slope of the line is 0.993. A positive slope indicates a positive linear relationship between city mpg and highway mpg.
The slope of a regression line represents the change in the dependent variable (in this case, highway mpg) for a one-unit increase in the independent variable (city mpg).
In this equation, the slope is given by 0.993. This means that for every one-unit increase in city mpg, the highway mpg is expected to increase by 0.993 units.
The positive numerical value of the slope indicates that there is a positive linear relationship between city mpg and highway mpg. This means that as the city mpg increases, the highway mpg also tends to increase.
#SPJ12
A. 67.5°
B. 30°
C. 22.5°
D. 45°
Answer:
B. 30
Step-by-step explanation:
A. y (x + 4) (x + 5)
Answer:
D. y =
Step-by-step explanation:
The solutions to this graph (meaning when y equals 0 or when the graph crosses the x-axis) are 4 and 5.
The only answer choice that has the solutions 4 and 5 when you factor it out is D.
Here's the proof:
Factors of 20: - 5 & -4
Sums that add up to -9: -5 + (-4)
(factor the first two terms and the last two terms separately)
(x - 5) (x - 4)
Hope it helps (●'◡'●)
Answer: 6 hours
Step-by-step explanation:
You have to divide 360 by 60 minutes.
Answer:
There are 360 minutes in 6 hours.
Hope this helps :)
Answer:
15 or -23
Step-by-step explanation:
I think you probably already turned this in but in case you haven't:
ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?
So there's two directions we could go.
Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)
But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)
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