Find the distance cd rounded to the nearest tenth. c=(8,-3) and D=(-9,-6)

Answers

Answer 1
Answer:

The distance CD rounded to the nearest tenth is approximately 17.3 units.

Here, we have to find the distance CD between points C(8, -3) and D(-9, -6), we can use the distance formula:

Distance CD = √[(x₂ - x₁)² + (y₂ - y₁)²]

where (x₁, y₁) are the coordinates of point C and (x₂, y₂) are the coordinates of point D.

Substitute the values:

Distance CD = √[(-9 - 8)² + (-6 - (-3))²]

Distance CD = √[(-17)² + (-3)²]

Distance CD = √[289 + 9]

Distance CD = √298

Now, round the result to the nearest tenth:

Distance CD ≈ 17.262

So, the distance CD rounded to the nearest tenth is approximately 17.3 units.

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Answer 2
Answer:
  • Distance Formula: √((x_2-x_1)^2+(y_2-y_1)^2)

Plug the coordinates into the distance formula and solve as such:

CD=√((8-(-9))^2+(-3-(-6))^2)\nCD=√(17^2+3^2)\nCD=√(289+9)\nCD=√(298)\nCD\approx 17.3

Your answer is 17.3 units.


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