Select the two binomials that are factors of this trinomial x2+10x+16

Answers

Answer 1

Answer:

So for this trinomial, I will be factoring by grouping. Firstly, what two terms have a product of 16x^2 and a sum of 10x? That would be 8x and 2x. Replace 10x with 2x + 8x:

$x^2+2x+8x+16$

Next, factor x^2 + 2x and 8x + 16 separately. Make sure that they have the same quantity inside the parentheses: $x(x+2)+8(x+2)$

Now you can rewrite this as $(x+8)(x+2)$ , which is your final answer.

Answer 2

Answer:

Answer: (x+8) and (x+2)

Step-by-step explanation:

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(2√5 + 3√7)^2 show your work and justify each step. Thank you!
1. Find the midpoint of the segment with the endpoints: (5,9) and (-7-7)

A dilation is a reduction if the scale factor is _____

Answers

It is the only invariant point under a dilation. may be written: Dk (x, y) = (kx, ky). If the scale factor, k, is greater than 1, the image is an enlargement (a stretch). If the scale factor is between 0 and 1, the image is a reduction (a shrink).

Is knowing the coordinates of the vertex of a parabola enough to determine the domain and range?a.No: we would have no information about the domain.
b.Yes: if the vertex is at (m,n), then the domain is all reals and the range is y ≤ n.
c.No: we would need to know if the vertex is a minimum or a maximum.
d.Yes: if the vertex is at (m,n), then the domain is all reals and the range is y ≥ n.

Use a graphing calculator to approximate the vertex of the graph of the parabola defined by the following equation.

y=2x-x+6

A)( 0.25, 6.125)
B)(-0.25, 5.875)
C)( 0.25, 5.875)
D)( 0.25, 6)

Answers

The correct answers are:

C) No: we would need to know if the vertex is a minimum or a maximum; and

C)( 0.25, 5.875).

Explanation:

The domain of any quadratic function is all real numbers.

The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.

If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.

There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.

The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).

AB¯¯¯¯¯ and BC¯¯¯¯¯ are tangent to ⊙ O. Identify BC.

Answers

Answer:

Step-by-step explanation:

$2(3x-7)=4x+8\nx=11\n4(11)+8=52$

On a vacation to Puerto Rico Rose jumped off a cliff into a river in Elion forest preserve her height as a function of time to be modeled by the function HFT equal 16 T squared +16 T +480 where T is the time after jumping in seconds and H is the height in feet how many seconds it take Rose to hit the water round your answer to the nearest hundredth

Answers

To solve for t, you will use the equation given: -16t^2 + 16t + 480 = 0. First, simplify the equation by dividing everything by 16: -t^2 + t + 30 = 0. Then complete reverse FOIL: (-t + 6)(t + 5) = 0. Next, set each of these equations to 0 separately, and solve for t. You will get t = 6, and t = -5. Since time can't be negative (Rose can't have hit the water after a negative number of seconds), the answer is 6.

C^4 divided by c^3

Please help

Answers

Step 1:

→ ${c}^(4) / {c}^(3)$

Step 2:

→ $\frac{ {c}^(4) }{ {c}^(3) }$

Step 3:

→ ${c}^(4 - 3)$

Step 4:

→ ${c}^(1)$ (c¹ and c is same thing)

________________________________

with regards!

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Answer:

Answer is C

Step-by-step explanation:

i.e (c x c x c x c) / (c x c x c) = c^1 = c

the length of the hypotenuse of a 30-60-90 triangle is 22 meters find the length of the side opposite 30 degree angle

Answers

$This\ triangle\ is\ a\ half\ of\ equilateral\ triangle\ which\ sides\ are\ 22\ m.\n\ so:\nside\ opposite\ 30\ degree\ angle\ is\ height\ of\ this\ equilateral\ triangle:\nh= (a\sqrt3)/(2),\ where\ a=22\nh= (22\sqrt3)/(2)=11\sqrt3\n\nLength\ of\ the\ side\ opposite\ 30\ degrees\ is\ 11\sqrt3$

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