Find three numbers that each have a multiple of 30.

Answers

Answer 1

Answer: I'm guessing you mean "What are three multiples of 30?" so 60, 90, 120 OR 5 x 6 = 30, 3 x 10 = 30, 15 x 2 = 30.

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Kevin buys a car. His car payment is $248 per month.After 55 payments how much was Kevin paying?

Answers

Answer:

hes paid 13,640

Step-by-step explanation:

Adriana's soccer ball is covered with a pattern of pentagons and hexagons in the ratio of 3 to 5. If there are 12 pentagons, how many hexagons are in the pattern?

Answers

Hello There!

This is a multiple step problem, to solve this you have to multiply and divide.

Steps
1. Divide 12 by 3

2. You should get 4, to check you're answer do 3*4 which equals 12

3. To find how many hexagons there are, you have to do 4*5 which equals 20

So, on Adriana's soccer ball if there are 12 pentagons, there should be 20 hexagons.

Hope This Helps :)

What kind of solution(s) do you expect for the linear equation:A. one solution

B. no solution

C. more than one solution

Answers

Answer:

A.) One Solution

Step-by-step explanation:

A system of linear equations usually has a single solution, but sometimes it can have no solution (parallel lines) or infinite solutions (same line). This article reviews all three cases. One solution. A system of linear equations has one solution when the graphs intersect at a point.

(correct answer gets brainliest) hurry please :')

Answers

Answer:

(3/5)^4 The correct answer is B.

The correct answer is b

Compare 3.21 and 0.2

Answers

3.21 is greater than 0.2

3.21 is greater than 0.2.

3.21 > 0.2

Which point is 7 units from (–2, 4)? A.
(–5, 4)

B.
(–2, 3)

C.
(5, 4)

D.
(9, 4)

Answers

The distance formula:
$d=√((x_2-x_1)^2+(y_2-y_1)^2)$

$(x_1,y_1)=(-2,4) \nd=7 \n \n7=√((x-(-2))^2+(y-4)^2) \n7=√((x+2)^2+(y-4)^2) \ \ \ |^2 \n49=(x+2)^2+(y-4)^2$
Check which point satisfies the equation:
$(x,y)=(-5,4) \n49 \stackrel{?}{=} (-5+2)^2+(4-4)^2 \n49 \stackrel{?}{=} (-3)^2+0^2 \n49 \stackrel{?}{=} 9 \n49 \not= 9 \ndoesn't \ satisfy \ the \ equation$

$(x,y)=(-2,3) \n49 \stackrel{?}{=} (-2+2)^2+(3-4)^2 \n49 \stackrel{?}{=} 0^2+(-1)^2 \n49 \stackrel{?}{=} 1 \n49 \not= 1 \ndoesn't \ satisfy \ the \ equation$

$(x,y)=(5,4) \n49 \stackrel{?}{=} (5+2)^2+(4-4)^2 \n49 \stackrel{?}{=} 7^2+0^2 \n49 \stackrel{?}{=} 49 \n49=49 \nsatisfies \ the \ equation$

$(x,y)=(9,4) \n49 \stackrel{?}{=} (9+2)^2+(4-4)^2 \n49 \stackrel{?}{=} 11^2+0^2 \n49 \stackrel{?}{=} 121 \n49 \not= 121 \ndoesn't \ satisfy \ the \ equation$

The answer is C.

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