MATHEMATICS HIGH SCHOOL

What number is 10 more than 64

Answers

Answer 1

Answer: the number that is 10 higher than 64 is 74.

Answer 2

Answer:

Final answer:

The number that is 10 more than 64 is 74. We find this by adding 10 to 64.

Explanation:

The question is asking for the number that is 10 more than 64. In mathematics, when we say 'more than', we are asking to add the numbers together. So, to find the number that is 10 more than 64, we simply add 10 to 64.

Here's how to do it:

Write down the number 64.
Add 10 to it.

So 64 + 10 = 74. Therefore, the number that is 10 more than 64 is 74.

Learn more about Addition here:

brainly.com/question/35006189

#SPJ2

Related Questions

What is the solution of the system defined by y = -x + 5 and 5x + 2y = 14?Ax=1/3, y=11/7 Bx=4/3, y=11/3 Cx=5/11,y=0 Dx=4/3,y=1
Simplify (3(3n-10) - 2n + 5). The solution for (n) is: a) 2n - 25 b) 5n - 35 c) 7n - 25 d) 7n - 25
In order to gather experts to advise him on federal policy, President George Washington createdCongress.the Constitution.a cabinet.departments.
Why can't you factor 2cosx^2+sinx-1=0 ?
Use the rules of multiplication by powers of 10 to calculate 20 times 100.

Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?

Answers

Some of the possible options of the questions are;

A) $(a - b) | \overline {a^2 + a \cdot b + b^2}$

B) $(a + b) | \overline {a^2 - a \cdot b + b^2}$

C) $(a + b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}$

D) $(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}$

The difference of two perfect cubes has a binomial factor and a trinomial factor

The option that gives the long division problem that can be used to prove the difference of two perfect cubes is option D

D) $\underline {(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}}$

Reason:

The formula for factoring the difference of twoperfect cubes is presented as follows;

a³ - b³ = (a - b)·(a² + a·b + b²)

Given that a factor of the difference of two cubes is (a - b), and that we

have; (a³ + 0·a·b² + 0·a²·b - b³) = (a³ - b³), both of which are present in

option D, by long division of option D, we have;

${} \hspace {33} a^2 + a \cdot b + b^2\n(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a^2 \cdot b - b^3}\n{} \hspace {33} \underline{a^3 - a^2 \cdot b }\n{} \hspace {55} a^2 \cdot b + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3\n {} \hspace {55} \underline{a^2 \cdot b - a \cdot b^2}\n{} \hspace {89} a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3\n{} \hspace {89} \underline{a \cdot b^2 - b^3}\n{}\hspace {89} 0$

By the above long division, we have;

$(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}$ = a² + a·b + b²

Which gives;

$(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}$ = (a³ + 0·a·b² + 0·a·b² - b³)/(a - b)

We get;

(a³ + 0·a·b² + 0·a·b² - b³)/(a - b) = a² + a·b + b²

(a - b)·(a² + a·b + b²) = (a³ + 0·a·b² + 0·a·b² - b³) = (a³ - b³)

(a - b)·(a² + a·b + b²) = (a³ - b³)

(a³ - b³) = (a - b)·(a² + a·b + b²)

Therefore;

The long division problem that can be used to prove the formula for

factoring the difference of two perfect cubes is

$(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}$ , which is option D

D) $(a - b) | \overline {a^3 + 0 \cdot a \cdot b^2 + 0 \cdot a \cdot b^2 - b^3}$

Learn more here:

brainly.com/question/17022755

Answer:

The correct options, rearranged, are:

Options:

$A)(a^2+ab+b^2)/(a-b)\n\nB)(a^2-ab+b^2)/(a+b)\n\nC)(a^3+0a^2+0ab^2-b^3)/(a+b))\n\n D)(a^3+0a^2+0ab^2-b^3)/(a-b)$

And the asnwer is the last option (D).

Explanation:

You need to find which long division can be used to prove the formula for factoring the difference of two perfect cubes.

The difference of two perfect cubes may be represented by:

$a^3-b^3$

And it is, as a very well known special case:

$a^3-b^3=(a-b)(a^2+ab+b^2)$

Then, to prove, it you must divide the left side, $a^3-b^3$ , by the first factor of the right side, $a-b$

Note that, to preserve the places of each term, you can write:

$(a^3-b^3)=(a^3+0a^2+0ab^2-b^3)$

Then, you have:

$(a^3+0a^2+0ab^2-b^3)=(a-b)(a^2+ab+b^2)$

By the division property of equality, you can divide both sides by the same factor, which in this case will be the binomial, and you get:

$(a^3+0a^2+0ab^2-b^3)/(a-b)=(a^2+ab+b^2)$

That is the last option (D).

1 over 3 +2over 5) x 2 over 3

Answers

1/3 + 2/5 • 2/3

2 • 2 = 4
5 • 3 = 15

1/3 = 5/15

5/15 + 4/15 = 9/15 = 3/5

1/3 + 2/5 • 2/3 = 3/5

Solve the following problem first using a tape diagram and then using an equation: In a school choir, 1/2 of the members were girls. At the end of the year, 3 boys left the choir, and the ratio of boys to girls became 3:4. How many boys remained in the choir?

Answers

Answer: 9 boys remained in the choir.

Step-by-step explanation:

Let x be the number of of boys and y be the number of girls.

In a school choir, 1/2(half) of the members were girls.

i.e $x=y$ (1)

At the end of the year, 3 boys left the choir, and the ratio of boys to girls became 3:4.

$(x-3)/(y)=(3)/(4)\n\n\Rightarrow\ 4(x-3)=3(y)\n\n\Rightarrow\ 4x-12=3y$

Put y= x from (1), we get

$4x-12=3x\n\n\Rightarrow\ 4x-3x=12\n\n\Rightarrow\ x=12$

Thus , the number of boys : x= 12

Boys remained in the choir = 12-3=9

construct the graph of x^2+y^2=9 what would this graph look like and what are its coordinates please help?

Answers

Answer:

The coordinates (3,0), (-3,0), (0,3) ,and (0,-3) helps us to draw the graph of the circle. Below is the explanation

Step-by-step explanation:

Given:

The equation of a circle is $x^(2) +y^(2) =9$ .

To find:

Graph the given equation.

Let's find the center and radius by comparing the given equation with the standard form.

$(x-h)^(2) +(y-k)^(2) =r^(2)$

We can rewrite our equation as $(x-0)^(2)+ (y-0)^(2)= 3^(2)$

Now, compare them

$(x-h)^(2) +(y-k)^(2) =r^(2)$

$(x-0)^(2)+ (y-0)^(2)= 3^(2)$

Center (h,k)=(0,0)

Radius r=3

Now, draw the graph of the circle by placing the center and radius.

So, the coordinates which are 3 units exactly from the center (0,0) help us to find the graph of the circle. So, (0,3), (0,-3), (3,0) ,and (-3,0) would help us to graph the circle.

You can learn more:

brainly.com/question/2870743

It would looks like circle with radius of 3 and its center at (0,0).

Solve for x. 7(x - 3) = 4(x + 5)

Answers

7(x-3) = 4(x+5)
7x - 21 = 4x + 20
7x - 4x = 20 + 21
3x = 41
x = 41/3
x = 13.67

5.567 round hundredths

Answers

5.57 because 5 is the tenths 6 is hundredths 7 is thousandths

556.7, I am really good at decimals and fractions, just mainly math, science, literature, and some Economics

Other Questions

In a rectangle CALM, LD =15cm. Find the length of diagonal CL. A. 15cm C. 25cm B. 20cm D. 30cm

Use multiplication to solve the proportion 35/28 = n/12

The equation of the line of best fit of a scatter plot is y = 12x + 7. What is the slope of the equation? −12 −7 12 7

Find the quotient -88, 11