Cuantas caras , aristas y vertices tiene un cono

Answers

Answer 1

Answer: Un cono tiene 1 vértice y 0 aristas.

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A shipping carton for a rolled-up poster has the shape of a triangular prism. Each end of the carton is a triangle with a base 6 inches long and a height of 5 inches. The length of the carton is 32 inches. If you answer we can chat ( : and I'll thank you in a big way!

Answers

I am guessing you are wanting to find the volume.

Volume= area of cross-section × length

The area of the cross-section is the triangle is 15 cm². 15 cm² × 32cm is 480cm³. Therefore the answer is 480cm³

If you are finding the surface area, the two triangles add up to 30cm. Then each rectangle is 160cm. There are 3 rectangles and 160x3= 480. 480+30= 510cm.

The surface area is 510cm and the volume is 480cm³.

Which expression describes 9 less than 5 times some number

Answers

Answer:

9 - 5x I think

Step-by-step explanation:

Find dy/dx if y= (1+x)e^x^2

Answers

$y=(1+x)e^(x^2)\ny'=(1+x)'\cdot e^(x^2)+(1+x)\cdot(e^(x^2))'\ny'=1\cdot e^(x^2)+(1+x)\cdot e^(x^2)\cdot (x^2)'\ny'=e^(x^2)+(1+x)e^(x^2)\cdot2x\ny'=e^(x^2)(1+(1+x)\cdot2x)\ny'=e^(x^2)(1+2x+2x^2)\ny'=e^(x^2)(2x^2+2x+1)\n$

You first need to know that:

$If\quad y=u\cdot v\n \n \frac { dy }{ dx } =u\frac { dv }{ dx } +v\frac { du }{ dx } \n \n$

Knowing that u is a function of x and that v is a function of x.

So:

$y=\left( 1+x \right) { e }^{ { x }^( 2 ) }=u\cdot v\n \n u=1+x,\n \n \therefore \quad \frac { du }{ dx } =1$

$\n \n v={ e }^{ { x }^( 2 ) }={ e }^( p )\n \n \therefore \quad \frac { dv }{ dp } ={ e }^( p )={ e }^{ { x }^( 2 ) }\n \n p={ x }^( 2 )\n \n \n \therefore \quad \frac { dp }{ dx } =2x$

$\n \n \therefore \quad \frac { dv }{ dp } \cdot \frac { dp }{ dx } =2x{ e }^{ { x }^( 2 ) }=\frac { dv }{ dx }$

And this means that:

$\frac { dy }{ dx } =\left( 1+x \right) \cdot 2x{ e }^{ { x }^( 2 ) }+{ e }^{ { x }^( 2 ) }\cdot 1\n \n =2x{ e }^{ { x }^( 2 ) }\left( 1+x \right) +{ e }^{ { x }^( 2 ) }$

$\n \n ={ e }^{ { x }^( 2 ) }\left( 2x\left( 1+x \right) +1 \right) \n \n ={ e }^{ { x }^( 2 ) }\left( 2x+2{ x }^( 2 )+1 \right) \n \n ={ e }^{ { x }^( 2 ) }\left( 2{ x }^( 2 )+2x+1 \right)$

Geometry. Please help ASAP.In the figure, PA and PB are tangent to circle O and PD bisects ∠BPA . The figure is not drawn to scale.

A. 78
B. 33
C. 90
D. 66

Answers

Please see the pic, I'd solved your question in it.

Which expressions are equivalent to 16x4 − 64? Check all that apply.16x4 + 16x – 16x – 64

16x4 – 8x – 8x – 64

(4x2 + 8)(4x2 – 8)

16(x2 + 2)(x2 – 2)

4(4x4 – 8)

Answers

A. 16x^4 + 16x - 16x - 64

C. (4x^2 + 8)(4x^2 - 8)

D. (16x^2 + 209x^2 - 2)

ListenWhich statement has x = 2 as its solution?
3x - 12 = 17
7(x + 1) = 14
1- 6x = -11
4x + 5 = 3

Answers

Answer: 1 - 6x = -11

Step-by-step explanation:

For each expression, substitute x for 2 to determine which is the correct expression:

3x - 12 = 17
3(2) - 12 = 17
6 - 12 = 17
-6 $\neq$ 17
Because the number on the left side of the equation doesn't equal the number on the right, this first equation is incorrect.

7(x + 1) = 14
7(2 + 1) = 14
7(3) = 14
21 $\neq$ 14
This second equation is incorrect as well.

1 - 6x = -11
1 - 6(2) = -11
1 - 12 = -11
-11 = -11
Because the number on the left equals the number on the right, the third equation is correct.

I hope this helps! :)

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