Geometry question, any help is appreciated
Geometry question, any help is appreciated - 1

Answers

Answer 1
Answer:

I would say a scatter plot.


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How is the graph of log (x – 5) translated from the graph of log x?

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Answer:

The graph of y=logx shifts 5 units right to get the graph of y=log(x – 5).

Step-by-step explanation:

The parent log function is

y=\log x

The translation of the function is defined as

y=\log (x+a)+b                .... (1)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

The given function is

y=\log (x-5)               .... (2)

From (1) and (2), we get

a=-5,b=0

Since a=-5<0, therefore the graph of y=logx shifts 5 units right to get the graph of y=log(x – 5).

The transformation of g(x) to f(x) is g(x) is shifted left by 5 unit to f(x).

Describing the transformation of f(x) to g(x).

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = log(x - 5)

g(x) = log(x)

So, we have

Difference = 5 - 0

Evaluate

Difference = 5

This means that the transformation of g(x) to f(x) is g(x) is shifted left by 5 unit to f(x).

Read more about transformation at

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A student drops a penny from the top of a tower and decides that she will establish a coordinate system in which the direction of the penny's motion is positive. what is the sign of the acceleration of the penny?

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Answer:

The sign of acceleration is positive.

Step-by-step explanation:

Consider the provided information.

It is given that A student drops a penny from the top of a tower and decides that she will establish a coordinate system in which the direction of the penny's motion is positive.

Here the direction of the velocity is positive,  and the velocity is increasing.

Acceleration is defined as the rate at which an object changes its velocity.

Since velocity is positive therefore the acceleration is also positive.

Hence, the sign of acceleration is positive.

Answer:

It's positive

Step-by-step explanation:

Explain why 1.19 is the greatest amount of money it is possible to have without being able to make change for a dollar

Answers

Hello,

There are only 2 solutions for $1.19

In cents:
119=1*25+9*10+0*5+4*1
119=3*25+4*10+0*5+4*1

Thus
120=119+1=(1*25+9*10+0*5+4*1) +1 =1*25+9*10+0*5+5*1
but 1*25+7*10+0*5+5*1=100

120=119+1=(3*25+4*10+0*5+4*1)+1=3*25+4*10+0*5+5*1
but 3*25+2*10+0*5+5*1=100

So there are no solution for $1.20


Kali spent half of her weekly allowance on clothes. To earn more money her parents let her clean the gutters for $9. What is her weekly allowance if she ended with $13?

Answers

Kali weekly allowance if she ended with $13 would be $8.

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

we have been given the information as;

Kali spent half of her weekly allowance on clothes.

After Kali spent half of her allowance and earned $9, she is left with $13.

This means the remaining of her weekly allowance is $9.

This can be derived by subtracting $9.

$13 - $9 = $4

This means that it is $4 that remains after spending half of her weekly allowance.

Therefore, her weekly allowance = $4 x 2 = $8

Hence, Kali weekly allowance if she ended with $13 would be $8.

Learn more about the unitary method;

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So to find the answer to this, you have to consider that (1)/(2) x + 9 = 13 - half because half the pocket money (x) was spend on clothes, then plus 9 because that's how much extra she gained and 13 because that was the result of all the changes.

To solve this, first subtract 9 from both side, which leaves you with (1)/(2) x = 4 and (1)/(2) x is the same as (1x)/(2), so to solve this, multiply both sides of the equation by two, resulting in x = 8. SO from this we can conclude that the weekly allowance is $8

A train left Vadodara at 4:40p.m on Monday and reached Guwahati on Thursday at 12:30 pm. find the total duration of the journey.

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