Great question. Let's let r be a rational number and s be irrational. Note r has to be nonzero for this to work. In other words, it's not true that when we multiply zero, a rational number, by an irrational number like π we get an irrational number. We of course get zero.
The question is: why is the product
irrational?
In math "why" questions are usually answered with an illuminating proof. Here the indirect proof is enlightening.
Suppose p was rational. Then
would be rational as well, being the ratio of two rational numbers, so ultimately the ratio of two integers.
But we're given that s is irrational so we have our contradiction and must conclude our assumption that p is rational is false, that is, we conclude p is irrational.
A proof by contradiction.
Let assume that the product of a rational number and an irrational number is rational.
Let and be rational numbers, where and an irrational number.
Then
Integers are closed under multiplication, therefore and are integers, making the number rational, which is contradictory with the earlier statement that is an irrational number.
Answer:
Explanation
The capacity of the shelter is a constant. It is 80 people × 14 days.
That is an inverse relation: the product of the number of people and the number of days will be always the same.
As the number of people decreases the number of days that the food lasts increases, in a proportion such that the product of the days and the number of people is the same.
Thus, for 32 people the number of days the food lasts is x, such that:
Solving for x:
The food will last 35 days.
Answer: 35 days
Step-by-step explanation:
Given: A shelter has enough food to feed an average of 80 hungry people a day for 14 days.
Let y be the number of days if 32 people are at the shelter .
The number of hungry people and number of days are in inverse proportion
Therefore,
Therefore, if an average of 32 people are at the shelter each day, the food will last for 35 days.