As you increase the number of supporting strings, what happens to the force needed to lift the bottom block

Answers

Answer 1

Answer: the weight is spread across multiple different strings, allowing for each string to require dealing with a large amount of stress, because the stress is evenly distributed throughout each string. hope i helped :3

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.. An object has a mass of 40 000 kilogramsand a volume of 5 cubic metres. What is its
density?

Answers

Answer:

8000 kg/cm^3

Explanation:

The density formula is P = M/V

Density = P = ? expressed in kg/m^3

M = mass = 40,000 kg

V = volume = 5 m^3

P = 40,000/5

P = 8000 kg/m^3

Which example involves the transformation of chemical energy directly into light energy? A) a wind mill
Reactivate

B) a glow stick
C) photosynthesis
D) a hydroelectric dam

Answers

The question involves the concepts of chemical energy, light energy and energy conversion.

The example which involves the transformation of chemical energy directly into light energy is "B) a glow stick".

In a windmill, the input energy is the wind energy, and that wind energy is then converted to mechanical energy when the rotor blades rotatae. That mechanical energy is then converted to electrical energy. This electrical energy is then used in lamps to get light energy. Hence, the chemcial energy is not directly transformed into light energy in the windmill.

A glow stick uses the chemical energy from the chemicals inside it to produce luminance in the form of light energy. When the stick is bent or broken, it releases the chemicals inside it which undergo a chemical reaction that leads to the conversion of chemical energy into light energy.

During photosynthesis, light energy is used by plants to produce oxygen and energy in the form of sugar (glucose).

A hydroelectric dam receives mechanical energy from water. The gravitational potential energy of water due to its height is converted into kinetic energy when it reaches the turbine. This kinetic energy is then converted to electrical energy.

Hence, the only example where chemical energy is directly converted to light energy is Glow Stick.

Learn more about energy conversion here:

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The attached picture shows different energy conversions.

a glow stick because when you crack it in the dark it turns into a light that works in the dark

Which temperature corresponds to standard temperature as 0 degrees Celsius? a. 273 K b. 100 K c. 32 K d. 0 K

Answers

Answer:

A.) 273 K

Explanation:

Standard temperature, often referred to as standard room temperature, is defined as 0 degrees Celsius (0°C). To convert this temperature to Kelvin (K), you can use the following formula:

K = °C + 273.15

So, to find the temperature in Kelvin corresponding to 0 degrees Celsius:

K = 0°C + 273.15 = 273.15 K

Therefore, the temperature corresponding to standard temperature as 0 degrees Celsius is:

a. 273 K

An object of the same mass has three different weights at different times. Which statement is possible?

Answers

So we want to know how can an object have three different weights at different times. So weight is Fg=m*g, where m is the mass of the objecct and g is the gravitational acceleration. On Earth, g=9.81 m/s^2, in space g is much less and on the moon g=1.625 m/s^2 So we see that the object changes its weight by moving it to space and on the Moon.

The object started on earth, was transported to space,and was deposited on the moon

Which of the following is not a state of matter?a. solid
b. liquid
c. water
d. plasma

Answers

Water doesn't belong on that list.

If it's removed, then there's a space to add GAS, which does belong.

A gas is heated from 263 K to 298 K, and the volume is increased from 24 L to 35 L. If the original pressure is 1 atm, what would the final pressure be? *

Answers

Since for closed system moles of the gas is always conserved

so as per idea gas equation we can say

$n = (PV)/(RT)$

so here we can say

$n_1 = n_2$

so here we have

$(P_1V_1)/(RT_1) = (P_2V_2)/(RT_2)$

as we know that

$T_1 = 263 K$

$T_2 = 298 K$

$V_1 = 24 L$

$V_2 = 35 L$

$P_1 = 1 atm$

now from above equation

$(1*24)/(263) = (P*35)/(298)$

on solving above equation we have

$P = 0.78 atm$

so here pressure will be 0.78 atm

Final answer:

Based on the combined form of the ideal gas law, the final pressure of the gas, given the changes in volume and temperature, would be approximately 0.725 atm.

Explanation:

The question concerns the change in conditions of a gas and asks you to determine the final pressure. This deals with the combined form of the ideal gas law, which states that the product of the initial pressure and volume, divided by the initial temperature, equals the product of the final pressure and volume, divided by the final temperature (P₁V₁/T₁ = P₂V₂/T₂).

Given that the initial pressure P₁ is 1 atm, initial volume V₁ is 24 L, initial temperature T₁ is 263 K, final volume V₂ is 35 L, and final temperature T₂ is 298 K, we can substitute these values into the equation to solve for the final pressure P₂.

Therefore, P₂ = P₁V₁T₂ / V₂T₁ = (1 atm × 24 L × 298 K) / (35 L × 263 K) ≈ 0.725 atm. So, the final pressure of the gas would be approximately 0.725 atm.

Learn more about Ideal Gas Law here:

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