There are 20 sticks per panel on a soccer ball. A soccer ball has 32 leather panels. How many stiches in all.

Answers

Answer 1

Answer: 20/1 × x/32
20×30=x
600=x
Answer: there are 600 stitches on a soccer ball.

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What is the combined version of the equations 5.2*10^6 and 2.47*10^8

Answers

Answer:To solve the system of equations using substitution, we'll start by solving one equation for one variable, and then substitute that expression into the other equation.

Let's solve the second equation, y = 3x - 7, for y:

y = 3x - 7 (Equation 2)

Now, we can substitute this expression for y in the first equation, 2x + y = 3:

2x + (3x - 7) = 3

Combining like terms, we have:

5x - 7 = 3

Adding 7 to both sides of the equation, we get:

5x = 10

Dividing both sides of the equation by 5, we have:

x = 2

Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use Equation 2:

y = 3x - 7

Substituting x = 2, we have:

y = 3(2) - 7

Simplifying the expression, we get:

y = 6 - 7

y = -1

Therefore, the solution to the system of equations is x = 2 and y = -1.

We can also check this solution by substituting the values of x and y back into both original equations to make sure they satisfy both equations.

A pooling equilibrium exists as long as the number of Type H customers in the market is relatively low.

True or False

A pooling equilibrium exists as long as the number of Type H customers in the market is relatively high.

True or False

Brainly Ginny character avatar

AI-generated answer

A pooling equilibrium exists when all customers, regardless of their type, are offered the same product or service. In a pooling equilibrium, the market does not differentiate between different customer types.

Given the statement "A pooling equilibrium exists as long as the number of Type H customers in the market is relatively low," we can analyze its truthfulness:

If the number of Type H customers in the market is relatively low, it means that there are fewer customers of Type H compared to other types. In this scenario, it is more likely that the market will offer a single product or service that caters to the majority of customers, including non-Type H customers. Therefore, it is true that a pooling equilibrium is more likely to exist when the number of Type H customers is relatively low.

On the other hand, if the number of Type H customers in the market is relatively high, it means that there is a significant presence of Type H customers. In this case, the market might be inclined to offer specialized products or services that specifically cater to the needs and preferences of Type H customers. This would result in a segmentation or differentiation of the market, which contradicts the concept of a pooling equilibrium. Therefore, it is false to say that a pooling equilibrium exists when the number of Type H customers is relatively high.

To summarize:

- A pooling equilibrium is more likely to exist when the number of Type H customers in the market is relatively low. (True)

- A pooling equilibrium is less likely to exist when the number of Type H customers in the market is relatively high. (False)

what is the combined version of the equations 5.2*10^6 and 2.47*10^8

Brainly Ginny character avatar

AI-generated answer

To find the combined version of the given equations 5.2*10^6 and 2.47*10^8, we need to add or subtract the numbers and keep the same power of 10.

The numbers in scientific notation have two parts: the coefficient and the power of 10. In this case, we have:

5.2 * 10^6 and 2.47 * 10^8

To combine them, we need to make sure that the powers of 10 are the same. We can do this by adjusting the coefficients.

First, let's adjust the coefficient of 5.2*10^6. We can do this by multiplying it by 10^2:

5.2 * 10^6 * 10^2 = 5.2 * 10^(6+2) = 5.2 * 10^8

Now that we have adjusted the coefficient of 5.2*10^6, we can combine it with 2.47*10^8:

5.2 * 10^8 + 2.47 * 10^8 = (5.2 + 2.47) * 10^8 = 7.67 * 10^8

Therefore, the combined version of the equations 5.2*10^6 and 2.47*10^8 is 7.67*10^8.

Find the sum of place value of 5 in the no 505

Answers

Place values are determined by the position of a digit in the number multiplied by 10 for each digit it has to its right.

Since there are two "5" digits in the number, let us break them down to their respective place values.

1.) 5: one's place: 5
2.) 5: hundred's place: 5 x 10 x 10 = 500

Adding the place values:
500 + 5 = 505

Therefore the sum is 505.

Rex paid $250 in taxes to the school district that he lives in this year. This year's taxes were a 12% increase from last year. What did Rex pay in school taxes last year?

Answers

Answer:

$223.21

Step-by-step explanation:

Last year the amount of taxes was x, an unknown amount. That was 100% of last year's tax cost.

This year, taxes went up by 12%, so this year the taxes are 112% of what they were last year. This year the taxes were 112% of x, and they were $250.

112% of x = 250

1.12x = 250

x = 250/1.12

x = 223.21

Answer: $223.21

The table below shows data from a survey about the amount of time students spend doing homework each week. The students were either in college or in high school:High Low Q1 Q3 IQR Median Mean σ
College 20 6 8 18 10 14 13.3 5.2
High School 20 3 5.5 16 10.5 11 11 5.4

Which of the choices below best describes how to measure the spread of this data?
A. Both spreads are best described with the IQR.
B. Both spreads are best described with the standard deviation.
C. The college spread is best described by the IQR. The high school spread is best described by the standard deviation.
D. The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

Answers

Answer:

C. The college spread is best described by the IQR. The high school spread is best described by the standard deviation.

Step-by-step explanation:

If data is normally distributed we use Standard deviation otherwise we use Interquartile Range (IQR) for measuring the spread.

Further, data is said to be normally distributed if Mean = Median = Mode.

So, High School data is normally distributed but College data is not.

So, We measure the spread of College data by IQR and High School data by Standard Deviation.

Thus, Option C is the only correct option.

Complete the square and wright in standard form x^2+y^2-8x-12+52=36

Answers

x² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
(x² - 8x + 16) + (y² - 12y + 36) = 88 + 16 + 36
(x - 4)² + (y - 6)² = 138
(h, k) = (x, y) = (4, 6)

$x^2+y^2-8x-12y+52=36 \nx^2-8x+16+y^2-12y+36-16-36+52=36 \n(x-4)^2+(y-6)^2-52+52=36 \n\boxed{(x-4)^2+(y-6)^2=36}$

One number is five more than another, and their sum is three less than three times the smaller. Find the numbers.If x represents the smaller number, which equation could be used to solve for x?

A. x 2 + 5 = 3x - 3
B. 2x + 5 = 3x - 3
C. 2x + 5 = 3(x - 3)